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Black_prince [1.1K]
3 years ago
9

Fredrick did an investigation on mass and acceleration. He applied a force to a toy car and measured the distance it moved. He t

hen taped weights of different masses to the car and applied the same force. He entered his observations in a table.
Fredrick’s Investigation
Mass Distance
car 250 grams 4.2 meters
car + 50 grams 300 grams 3.8 meters
car + 100 grams 350 grams 3.0 meters

Which statement correctly interprets the data?
A. Mass has no effect on acceleration.
B. More mass results in less acceleration.
C. More force results in greater acceleration.
D. More mass results in greater acceleration.
Physics
1 answer:
garik1379 [7]3 years ago
6 0

Explanation:

B. More mass results in less acceleration.

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A highly volatile substance has an initial mass of 1200 g and its mass is reduced by 12% each second.
Softa [21]

Answer:

Explanation:

a) 1.00 - 0.12 = 0.88

m = 1200(0.88)^t

b) t = ln(m/1200) / ln(0.88)

c) m = 1200(0.88)^10 = 334.20 g

d) t = ln(10/1200) / ln(0.88) = 37.451... = 37 s

e) t = ln(1/1200) / ln(0.88) = 55.463... = 55 s

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How do units of work and power compare
timurjin [86]

Answer:

Jule

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3 0
3 years ago
Billy pulls his friend Sue on a sled at a constant velocity with a horizontal force of 200 N. The weight of the sled and Sue is
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After an initial test run John determines that his cooling system generates 45 W of heat loss. Calculate the amount of heat loss
anyanavicka [17]

Given:

heat generated by John's cooling system,  H = \rho A v^{3}  = 45 W    (1)

If ρ, A, and v corresponds to John's cooling system then let \rho_{1}, A_{1}, v_{1} be the variables for Mike's system then:

\rho  = 9.5\rho_{1}

\rho_{1}  = \frac{\rho}{9.5}

v_{1} =3.5 v

Formula use:

Heat generated, H = \rho A v^{3}

where,

\rho = density

A = area

v = velocity

Solution:

for Mike's cooling system:

H_{2} = v_{1}^{3}{1}A_{1}\rho_{1}

⇒ H_{2} = (3.5v)^{3} × A × \frac{\rho}{9.5}

H_{2} = 4.513v^{3} A  \rho

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H_{2} = 4.513 × 45 = 203.09 W

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3 years ago
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