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finlep [7]
3 years ago
14

Which test was conducted on the skin found under the victim’s nails?

Physics
2 answers:
BARSIC [14]3 years ago
5 0
Y-STR analysis. It is a DNA test used to compute and match with the possibility via lap.
N76 [4]3 years ago
3 0
The answer to that question should be and I am pretty sure is, DNA.
You might be interested in
A bicycle is heading West. It goes 5000m in 500s what's its velocity
dybincka [34]
There are several information's of immense importance already given in the question. Based on the given information's the answer to the question can easily be determined.
Distance covered by the bicycle = 5000 meter
Time taken by the bicycle to reach the distance = 500 second.
Velocity of the bicycle = Distance / Time taken
                                   = 5000/500 meter/second
                                   = 50 meter/second
So the velocity of the bicycle is 50 meter per second. I hope the procedure is clear enough for you to understand. In future you can always use this procedure for solving similar problems.
8 0
3 years ago
If f3=0 and f1=12n, what does the magnitude of f⃗ 2 have to be for there to be rotational equilibrium?
QveST [7]

<span>I found out F2 and its correct just need help in solving the other parts </span>
<span>F2 = 4.5 N </span>
4 0
4 years ago
Explain why the coin is able to float on top of the water in this glass.
Alex787 [66]

Answer:

Surface tension is the result of water molecules pulling inward with a strong attractive force. This attractive force brings the molecules on the surface of the water close together and causes the surface of the water to be drawn toward the water molecules beneath the surface. Since there are no water molecules above the surface, there are uneven forces. This causes surface tension, allowing the coin to float on the water’s surface.

Explanation:

Brainliest pls

4 0
2 years ago
A 77.0 kg woman slides down a 42.6 m long waterslide inclined at 42.3. at the bottom, she is moving 20.3 m/s.how much work did f
svlad2 [7]

Answer:

W = 21409.2 J

Explanation:

Given,

The mass of the woman, m = 77 Kg

The length of the water slide, S = 42.6 m

The inclination of the water slide, ∅ = 42.3

The constant velocity of the women sliding, 20.3 m/s

The kinetic friction of the sliding force is given by the formula

                               Fₓ = μₓ η

Where,

                    μₓ - coefficient of kinetic friction

                     η - normal force acting on the body

Since the water slide is inclined at an angle and the person is sliding with constant velocity. The coefficient of friction becomes,

                     μₓ = tan∅

And,                η = mg cos∅

Therefore, the kinetic friction force becomes

                          Fₓ =  tan∅  mg cos∅

Substituting the given values in the above equation

                           Fₓ = 0.9 x 77 x 9.8 x 0,74

                               = 502.56 N

The work done by the kinetic friction on the person

                            W = Fₓ · S    

                                = 502.56 N x 42.6 m

                                = 21409.2 J

Hence, the work done by the friction on the woman is, W = 21409.2 J

8 0
3 years ago
What is the rotational inertia of an object that rolls without slipping down a 2.00-m-high incline starting from rest, and has a
krek1111 [17]

We will apply the concepts of energy conservation to solve the problem. We know that gravitational potential energy is equivalent to the sum of translational kinetic energy and rotational kinetic energy. Additionally, the relation of the angular velocity with the tangential velocity will be determined to eliminate the angular term and obtain the expression of the Inertia in terms of the data given, therefore, we know that

PE_{g} = KE_{trans} +KE_{rot}

mgh = \frac{1}{2} mv^2+\frac{1}{2}I\omega^2

The angular velocity in terms of tangential velocity and radius is defined as,

\omega = \frac{v}{R}

Replacing,

mgh = \frac{1}{2} mv^2+\frac{1}{2} I(\frac{v}{R})^2

Multiplying by R^2,

gh(mR^2) = \frac{v^2}{2} (mR^2)+\frac{v^2}{2}I

\frac{v^2}{2}I = (gh-\frac{v^2}{2})mR^2

I = (\frac{2gh}{v^2}-1)mR^2

Replacing with our values we have,

I = (\frac{2(9.8)(2)}{6^2}-1)mR^2

I = 0.089mR^2

6 0
3 years ago
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