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tekilochka [14]
3 years ago
14

How can you make your motor run in reverse? make sure to try it?

Physics
1 answer:
Karo-lina-s [1.5K]3 years ago
8 0
We are asked in what manner can one make the motor run in reverse. One way to do so is to flip the magnet on the other side so that the opposite charge faces to the motor. The magnetic field induced by the magnet to the motor results to a reactive force opposite to the induced motion. 
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Which description is evidence of chemical weathering?
Gelneren [198K]

Answer:

b.

Explanation: I do not know much about this but the answer that i think it is was b.

8 0
3 years ago
Name 2 things that have gears in them
Anvisha [2.4K]

BICYCLE

MOTOR BIKES

CARS

THEY ARE THE VEHICLES WHICH HAS GEARS IN THEM.

6 0
3 years ago
There is a 90 kg woman attached at the end of a bungee cord (k = 35 N/m) that is experiencing simple harmonic motion. How long d
Cloud [144]

Answer:

The value is T  =10.1 \ s

Explanation:

From the question we are told that

    The mass of the woman is  m  = 90 \  kg  

    The spring constant of the bungee cord is  k  =  35 \  N/  m

Generally the period of the oscillation (i,e time taken to complete on  cycle ) is mathematically represented as

            T  = 2 \pi *  \sqrt{ \frac{m}{k} }

=>      T  = 2 * 3.142  *  \sqrt{ \frac{90 }{ 35} }

=>      T  =10.1 \ s

3 0
3 years ago
2. Lenses such as those in microscopes and telescopes depend on which property of<br><br> light?
Marizza181 [45]

Answer:

The eyepiece comprises a converging lens that is a magnifying lens. The lens has a short focal length,

This lens magnifies this image.

Explanation:

In lenses such as those in microscopes and telescopes, the objective forms an image with the following features:

1. Image is real

2. Image is diminished in size

3. Also, the image formed is upside-down.

The eyepiece comprises a converging lens that is a magnifying lens. The lens has a short focal length,

This lens magnifies this image.

5 0
3 years ago
A frictionless piston-cylinder device contains 10 kg of superheated vapor at 550 kPa and 340oC. Steam is then cooled at constant
Alla [95]

Answer:

a) the work (W) done during the process is -2043.25 kJ

b) the work (W) done during the process is -2418.96 kJ

Explanation:

Given the data in the question;

mass of water vapor m = 10 kg

initial pressure P₁ = 550 kPa

Initial temperature T₁ = 340 °C

steam cooled at constant pressure until 60 percent of it, by mass, condenses; x = 100% - 60% = 40% = 0.4

from superheated steam table

specific volume v₁ = 0.5092 m³/kg

so the properties of steam at p₂ = 550 kPa, and dryness fraction

x = 0.4

specific volume v₂ = v_f + xv_{fg

v₂ = 0.001097 + 0.4( 0.34261 - 0.001097 )

v₂ = 0.1377 m³/kg

Now, work done during the process;

W = mP₁( v₂ - v₁ )

W = 10 × 550( 0.1377 - 0.5092 )

W = 5500 × -0.3715

W = -2043.25 kJ

Therefore, the work (W) done during the process is -2043.25 kJ

( The negative, indicates work is done on the system )

b)

What would the work done be if steam were cooled at constant pressure until 80 percent of it, by mass, condenses

x₂ = 100% - 80% = 20% = 0.2

specific volume v₂ = v_f + x₂v_{fg

v₂ = 0.001097 + 0.2( 0.34261 - 0.001097 )

v₂ = 0.06939 m³/kg

Now, work done during the process will be;

W = mP₁( v₂ - v₁ )

W = 10 × 550( 0.06939 - 0.5092 )

W = 5500 × -0.43981

W = -2418.96 kJ

Therefore, the work (W) done during the process is -2418.96 kJ

3 0
3 years ago
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