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Sveta_85 [38]
2 years ago
9

Two gliders collide on an air track. Glider 1 has a mass of 7.0 kg, and glider 2 has a mass of 4.0 kg. Before the collision, gli

der 1 had a velocity of 2.0 m/s, and glider 2 had a velocity of -5.0 m/s. If the collision is perfectly elastic, what is the total kinetic energy of both gliders after the collision?
A.-36.0 J
B. 36.0 J
C. 64.0 J
D. 128.0 J
Physics
1 answer:
steposvetlana [31]2 years ago
3 0
In an elastic collision, no energy is lost. The energy would be the same as before the collision.
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Consider a product with three components in​ series, with reliabilities of​ 0.90, 0.80, and 0.99 for components​ A, B, and​ C, r
Feliz [49]

Answer:0.853

Explanation:

Given

Reliability of A is 0.90

Reliability of B is 0.80

Reliability of C is 0.99

B has a backup with reliability of 0.8

i.e. B has a component in parallel to it.

A,B& C is series.

B actual reliability is

R_b=1-\left ( 1-0.8\right )\left ( 1-0.8\right )

R_b=0.96

Thus R_{net} is given by

R_{net}=R_A\times R_B\times R_C

R_{net}=0.9\times 0.96\times 0.99

R_{net}=0.8553

5 0
3 years ago
An environmental group wants to sink a ship off the coast to create an artificial reef. They find that they must get a permit fr
bazaltina [42]

Answer:

The environmental protection agency needs to inspect the ship and make sure it is safe before giving the ok.

Explanation:

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4 0
3 years ago
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Two large, parallel, nonconducting sheets of positive charge face each other. What is at points (a) to the left of the sheets, (
alexira [117]

Answer:

a)The electric Field will be zero at the point between the sheets

b)E_1=\dfrac{\sigma}{\epsilon_0}

c)E_2=\dfrac{\sigma}{\epsilon_0}

Explanation:

Let \sigma be the surface charge density of the of the non conducting parallel sheet.Let consider a Gaussian surface in the form of of cylinder such that its cross-sectional is A . Then there will be flux only due to cross sectional area as the curved sectional is perpendicular to the the electric field  so the Electric Flux due to it is zero.

Now using Gauss law we have, E be the electric Field at the distance r from the sheet then

E\times 2A=\dfrac{\sigma A}{\epsilon_0}\\E=\dfrac{\sigma}{2\epsilon_0}

The Field will be away from the sheet and perpendicular to it.

a) The Electric Field between them

E_1=\dfrac{\sigma}{2\epsilon_0}-\dfrac{\sigma}{2\epsilon_0}\\=0

b)The Electric Field to the right of the sheets

E_1=\dfrac{\sigma}{2\epsilon_0}+\dfrac{\sigma}{2\epsilon_0}\\=\dfrac{\sigma}{\epsilon_0}

c)The Electric Field to the left of the sheets

E_2=\dfrac{\sigma}{2\epsilon_0}+\dfrac{\sigma}{2\epsilon_0}\\=\dfrac{\sigma}{\epsilon_0}

3 0
3 years ago
A_ is a cut made through the wood
Cloud [144]

Answer:

i believe the answer is B only because i looked it up on g00gle so take what i say with a GRAIN of salt all puns intended

Explanation:

 

6 0
3 years ago
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If a transformer has 50 turns in the primary winding and 10 turns on the secondary winding, what is the reflected resistance in
Elza [17]

Answer:

The reflected resistance in the primary winding is 6250 Ω

Explanation:

Given;

number of turns in the primary winding, N_P = 50 turns

number of turns in the secondary winding, N_S = 10 turns

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Determine the turns ratio;

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Now, determine the reflected resistance in the primary winding;

\frac{R_P}{R_S} = K^2\\\\R_P = R_SK^2\\\\R_P = 250(5)^2\\\\R_P = 6250 \ Ohms

Therefore, the reflected resistance in the primary winding is 6250 Ω

6 0
3 years ago
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