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Sveta_85 [38]
2 years ago
9

Two gliders collide on an air track. Glider 1 has a mass of 7.0 kg, and glider 2 has a mass of 4.0 kg. Before the collision, gli

der 1 had a velocity of 2.0 m/s, and glider 2 had a velocity of -5.0 m/s. If the collision is perfectly elastic, what is the total kinetic energy of both gliders after the collision?
A.-36.0 J
B. 36.0 J
C. 64.0 J
D. 128.0 J
Physics
1 answer:
steposvetlana [31]2 years ago
3 0
In an elastic collision, no energy is lost. The energy would be the same as before the collision.
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6 0
3 years ago
2. Adelia holds a shiny steel spoon with its back (convex surface) facing her eyes at a distance
My name is Ann [436]

Answer:

(a) The convex mirror image, is always upright at all positions, while images formed by concave mirrors are always inverted when the object distance from the mirror is more than the mirrors focal length.

(b) An upright image is not seen for object at a distance from a concave mirror further than the focal length of the mirror, which is the spoon in the question

Therefore, the location of her eyes of approximately, 30 cm,  from the mirror is more than the mirror's focal length

Explanation:

3 0
3 years ago
A stunt woman attempts to swing from the roof of a m 24 high building to the bottom of an identical building using a m 24 rope,
MakcuM [25]

Answer:

Height from ground is 8 m where string will break

Explanation:

Let the string makes some angle with the vertical after some instant of time

So here we have

T - mg cos\theta = \frac{mv^2}{R}

T = mg cos\theta + \frac{mv^2}{R}

now by energy conservation we have

\frac{1}{2}mv^2 = mg(R cos\theta)

mv^2 = 2mgR cos\theta

T = mg cos\theta + 2mgcos\theta

T = 3mg cos\theta

For string break down we have

T = 2mg = 3mgcos\theta

cos\theta = \frac{2}{3}

Now height from the ground is given as

h = R - Rcos\theta

h = 24 - 24(\frac{2}{3})

h = 8 cm

7 0
3 years ago
A wire that is 0.86 meters long is moved perpendicularly through a constant magnetic field of strength 0.035 newtons/amp·meter a
avanturin [10]
<span>The answer to your question is choice: D</span>
8 0
2 years ago
Read 2 more answers
A round object of mass 10 kg and radius 0.5 m rolls without slipping down a hill from a height of 4.5 m. If its speed at the bot
Mice21 [21]

Answer:

moment of inertia is 2.72 kg m²

Explanation:

given data

mass m = 10kg

height h = 4.5 m

radius r  = 0.5 m

speed  v = 6.5 m/s

to find out

moment of inertia

solution

we apply here conservation of energy

that is

mgh = 1/2 ×mv² + 1/2 × Iω²

here I is moment of inertia we find and

we know ω = Velocity / radius = 6.5 / 0.5 = 13

and g = 9.8

so put here all these value

10 (9.8) 4.5 = 1/2 ×(10)(6.5)² + 1/2 × I(13)²

441 = 211.25 + 1/2 × I( 169 )

I = 2.72

so moment of inertia is 2.72 kg m²

7 0
3 years ago
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