Answer:
553.1m
Explanation:
When an object moves at constant velocity we can express this movement like V=x/t, where V is the velocity, x is the displacement and t is the time spent on it.
In that way, the expression x=V.t give us the displacement from t=0s until t=51s, but we have to sum the initial distance from the point A.
x=242m +V.t = 242m + (6.1m/s x 51s) = 553.1m
Explanation:
m = kg. v=m/s. g=m/s^2. h= m
>>1/2mv^2=mgh
>>1/2mv^2=mgh>> kg*(m/s)^2= kg*m/s^2*m
>>1/2mv^2=mgh>> kg*(m/s)^2= kg*m/s^2*m>>kg m^2/s^2=kg m^2/s^2 the fraction 1/2 won't be able to make any changes to to the dimensional expression of energy i.e half of energy is still energy therefore you can neglect the number .
<u>>>kg m^2/s^2=kg m^2/s^2</u><u> </u>
<u>></u><u>></u><u>J</u>= J
<span>The equation to be used here would be:
v = u - gt
where u is the initial speed, g is the acceleration due to gravity and t is the time it takes
a)
u = 28 m/s, g = 9.8 m/s^2, t = 2s
v = 28 m/s - 9.8 m/s^2 * 2s = 8.4 m/s
after 2 s the lava bomb is still travelling upwards
b)
u = 28 m/s
g = 9.8 m/s^2 t = 3s
v = 28 m/s - 9.8 m/s^2 * 3s = -1.4 m/s after 3s the lave bomb is travelling downwards</span>
Answer:
The polytropic exponent (n) is 1.2
The amount of energy transfer by work is 552.45 Btu
Explanation:
P1V1^n = P2V2^n
P1 = 75 lbf/in^2 = 75 lbf/in^2 × 143.3 in^2/ft^2 = 10,747.5 lbf/ft^2
V1 = 4 ft^3/lb × 10 lb = 40 ft^3
P2 = 20 lbf/in^2 = 20 × 143.3 = 2866 lbf/ft^2
V2 = 12 ft^3/lb × 10 lb = 120 ft^3
(V2/V1)^n = P1/P2
(120/40)^n = 10747.5/2866
3^n = 3.75
ln 3^n = ln 3.75
n ln 3 = ln 3.75
n = ln 3.75/ln 3 = 1.2
W = (P2V2 - P1V1)/1 - n = (2866×120 - 10747.5×40)/1-1.2 = (343,920 - 429,900)/-0.2 = -85,980/-0.2 = 429,900 lbf.ft = 429,900/778.17 Btu = 552.45 Btu
Answer:
a tendency to do nothing or to remain unchanged.
Explanation:
