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pishuonlain [190]
4 years ago
8

While goofing off at the ice skating rink, a student takes off her shoes and places each of them on the ice. Her friend, a hocke

y player, then shoots a hockey puck at each shoe. The first puck immediately comes to rest after it collides with the left shoe. The second puck rebounds after it collides with the right shoe. If each hockey puck has the same incoming speed, which shoe has greater speed after the collision?
(A) left shoe
(B) right shoe
(C) both are the same
Physics
1 answer:
3241004551 [841]4 years ago
5 0

Answer:

The right shoe

Explanation:

Both shoes have the same speed.

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Answer:

In a collision, the velocity change is always computed by subtracting the initial velocity value from the final velocity value. If an object is moving in one direction before a collision and rebounds or somehow changes direction, then its velocity after the collision has the opposite direction as before.

Explanation:

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The current theory of the structure of the
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Answer:

pt 1: m=1.66698*10^{21} kg

Pt 2: KE=1212.23531 J

Explanation:

Information Given: (p = density)

l = 5200km  d = 35km p = 2700kg/m^{2}

Part 1: Mass

  • Find volume
  1. V=(l)^2(d)
  2. V=(4.2*10^6)^2(35*10^3)
  3. V=61.74*10^{16}
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Part 2: Kinetic Energy

  1. v=\frac{3.8cm}{yr}*\frac{m}{100cm}*\frac{yr}{365d}*\frac{d}{24hr}*\frac{hr}{3600s}
  2. v=1.20497*10^{-9}

KE=\frac{1}{2}mv^2

KE=\frac{1}{2} (1.66698*10^{21})(1.20497*10^{-9})^2

KE=1212.23531 J

Part 3: Jogger Speed

set up, because I don't have the mass :(

Information given:

KE_{jogger}

  1. KE=\frac{1}{2}mv^2
  2. v_{jogger} =\sqrt{\frac{2KE}{m_{jogger} } }
  • Input the values

Hope it helps :)

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In the picture, atoms 'A' and 'B' each have 3 protons in the nucleus,
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3 0
3 years ago
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