The answer is:
B. <span>X: Work is done to the system and temperature increases.
Y: Work is done by the system and temperature decreases.</span>
Given:
Total distance = 1000 kilometer
Total time = 5 hours
To find:
Average speed = ?
Formula used:
= ![\frac{s}{t}](https://tex.z-dn.net/?f=%20%5Cfrac%7Bs%7D%7Bt%7D%20%20)
Where
= average speed
s = total distance
t = total time
Solution:
Average speed of the jet is given by,
= ![\frac{s}{t}](https://tex.z-dn.net/?f=%20%5Cfrac%7Bs%7D%7Bt%7D%20%20)
Where
= average speed
s = total distance
t = total time
= ![\frac{1000}{5}](https://tex.z-dn.net/?f=%20%5Cfrac%7B1000%7D%7B5%7D%20%20)
= 200 km/ h
Thus, average speed of the jet is 200 km/h.
Hence, Option (A) is correct.
Answer:
A
Explanation:
because newton's second law states that if a resultant force acts on an object then, it will accelerate in the direction of the resultant force
They differ because they are transverse wave. That is their direction of travel is perpendicular to its vibrations.
There are some missing data in the text of the problem. I've found them online:
a) coefficient of friction dry steel piston - steel cilinder: 0.3
b) coefficient of friction with oil in between the surfaces: 0.03
Solution:
a) The force F applied by the person (300 N) must be at least equal to the frictional force, given by:
![F_f = \mu N](https://tex.z-dn.net/?f=F_f%20%3D%20%5Cmu%20N)
where
![\mu](https://tex.z-dn.net/?f=%5Cmu)
is the coefficient of friction, while N is the normal force. So we have:
![F=\mu N](https://tex.z-dn.net/?f=F%3D%5Cmu%20N)
since we know that F=300 N and
![\mu=0.3](https://tex.z-dn.net/?f=%5Cmu%3D0.3)
, we can find N, the magnitude of the normal force:
![N= \frac{F}{\mu}= \frac{300 N}{0.3}=1000 N](https://tex.z-dn.net/?f=N%3D%20%5Cfrac%7BF%7D%7B%5Cmu%7D%3D%20%5Cfrac%7B300%20N%7D%7B0.3%7D%3D1000%20N%20%20)
b) The problem is identical to that of the first part; however, this time the coefficienct of friction is
![\mu=0.03](https://tex.z-dn.net/?f=%5Cmu%3D0.03)
due to the presence of the oil. Therefore, we have: