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zhenek [66]
3 years ago
11

Season and date for this person

Physics
2 answers:
Tomtit [17]3 years ago
6 0

Answer:

summer June 21 is the answer

Yanka [14]3 years ago
4 0
Yess it’s June 21 summer:))
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Calculate the de broglie wavelength (in picometers) of a hydrogen atom traveling at 440 m/s.
Aleonysh [2.5K]

De broglie wavelength, \lambda = \frac{h}{mv}, where h is the Planck's constant,  m is the mass and v is the velocity.

h = 6.63*10^{-34}

Mass of hydrogen atom,  m = 1.67*10^{-27}kg

v = 440 m/s

Substituting

   Wavelength \lambda = \frac{h}{mv} = \frac{6.63*10^{-34}}{1.67*10^{-27}*440} = 0.902 *10^{-9}m = 902 *10^{-12}m

1 pm = 10^{-12}m\\ \\ So , \lambda =902 pm

So  the de broglie wavelength (in picometers) of a hydrogen atom traveling at 440 m/s is 902 pm

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E.  All of the Above

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What is the acceleration of a 1000kg car subject to a 550N net force?
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