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OLEGan [10]
3 years ago
12

If the primary of a transformer were connected to a dc power source,

Physics
1 answer:
QveST [7]3 years ago
8 0

Answer:

D. only briefly while being connected or disconnected.

Explanation:

As we know that transformer works on the principle of mutual inductance

here we know that as per the principle of mutual inductance when flux linked with the primary coil charges then it will induce EMF in secondary coil

So here when AC source is connected with primary coil then it will give output across secondary coil because AC source will have change in flux with time.

Now when we connect DC source across primary coil then it will not induce any EMF across secondary coil because DC source is a constant voltage source in which flux will remain constant always

So here in DC source the EMF will only induce at the time of connection or disconnection when flux will change in it while rest of the time it will give ZERO output

so correct answer will be

D. only briefly while being connected or disconnected.

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The specific heat of soil is 0.20 kcal/kg*C and the specific heat of water is 1.00 kcal/kg*C. This means that if 1 kg of soil an
stiv31 [10]

Answer: The soil will be 4\°C warmer than the water.

Explanation:

The heat (thermal energy) absorbed can be found using the following equation:

Q=m.C.\Delta T

Where:

Q is the heat  

m is the mass of the element

C is the specific heat capacity of the material.

\Delta T is the variation in temperature

<u>In the case of soil we have:</u>

Q_{soil}=m_{soil}.C_{soil}.\Delta T_{soil} (1)

Where:

Q_{soil}=1 kcal

m_{soil}=1 kg

C_{soil}=0.2 kcal/kg \°C

\Delta T_{soil}

<u>In the case of water we have:</u>

Q_{water}=m_{water}.C_{water}.\Delta T_{water} (2)

Where:

Q_{water}=1 kcal

m_{water}=1 kg

C_{water}=1 kcal/kg \°C

\Delta T_{water}

Isolating \Delta T from both equations:

\Delta T_{soil}=\frac{Q_{soil}}{m_{soil}.C_{soil}} (3)

\Delta T_{soil}=\frac{1 kcal}{1 kg(0.2 kcal/kg \°C)}

\Delta T_{soil}=5\°C (4)

\Delta T_{water}=\frac{Q_{water}}{m_{water}.C_{water}} (5)

\Delta T_{water}=\frac{1 kcal}{1 kg(1 kcal/kg \°C)}

\Delta T_{water}=1\°C (6)

Comparing (4) and (6) we can find the soil will be 4\°C warmer than the water.

8 0
3 years ago
An electric motor is traversed by 3.10²º electrons in 6 seconds. Determine the intensity of the current passing through the moto
Effectus [21]

Current is the amount of charged passed divided by elapsed time.

I = Q/Δt

I = current, Q = charge, Δt = elapsed time

We also know an electron has a charge of 1.6×10⁻¹⁹C, so let us find the total charge by multiplying this unit of charge by the total number of electrons:

Q = 1.6×10⁻¹⁹(3×10²⁰) = 48C

We also have Δt = 6s, so let's plug these values in to solve for I:

I = 48/6

I = 8A

4 0
3 years ago
PLEASE HELP ASAP...TIMED TEST. PLEASE ANSWER WITH AT LEAST A PARAGRAPH!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!
charle [14.2K]

Answer: I am pretty sure that you should pick radio waves.

Explanation: The scientist should use radio waves. I think this because you can use the radio waves to analyze the signals from outer space. This will work much better than anything there, to analyze it the best possible.

The best I could do.

8 0
3 years ago
A person would have a different weight on each planet. Arrange the planets in increasing order based on a person’s weight on the
Mars2501 [29]
Mercury, Uranus, Earth, Neptune.

Hope this helps!
5 0
4 years ago
Read 2 more answers
A defibrillator is a device used to shock the heart back to normal beat patterns. To do this, it discharges a 15 μF capacitor th
Citrus2011 [14]

Answer:

a)  q = 7.5 10⁻² C , b) 190 J , c)  I₀ = 50 A , d) 1.5 mC

Explanation:

The expression for capacitance is

            C = q / DV

            q = C DV

let's reduce the magnitudes to the SI system

            ΔV = 5 kV = 5000 V

            C = 15 μF = 15 10⁻⁶ F

              t = 90 μs = 90 10⁻⁶ s

            q = 15 10⁻⁶ 5000

            q = 7.5 10⁻² C

b) the energy in a capacitor is

             U = ½ C ΔV²

             U = ½ 15 10⁻⁶ 5000²

             U = 1,875 10² J

answer  190 J

c) At the moment the discharge begins, all the current is available and it decreases with time,

whereby

                V = I R

in the first instant I = Io

                I₀ = V / R

                I₀ = 5000/100

                I₀ = 50 A

but this is for a very short time

answer 50 A

d) The definition of current is

            i = dq / dt

in this case they give us the total current and the total time, so we can find the total charge

            i = q / t

            q = i t

            q = 17 90 10⁻⁶

            q = 1.53 10⁻³ C

answer is 1.5 mC

3 0
3 years ago
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