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Papessa [141]
3 years ago
7

The highest waterfall in the world is the Salto Angel in Venezuela. Its longest single falls has a height of 807 m. If water at

the top of the falls is at 17.3°C, what is the maximum temperature of the water at the bottom of the falls? Assume all the kinetic energy of the water as it reaches the bottom goes into raising its temperature.
Physics
1 answer:
valentina_108 [34]3 years ago
5 0

Answer:

Temperature at the bottom will be 19.18°C

Explanation:

We have given height h = 807 m

Temperature at the top =17.3^{\circ}C

Specific heat of water c = 4200 J/kg/^{\circ}C

From energy conservation

Kinetic energy at the bottom = potential energy at the top

So mc\Delta T=mgh

\Delta T=\frac{gh}{c}=\frac{9.8\times 807}{4200}=1.88^{\circ}C

So temperature at the bottom = 17.3+1.88 = 19.18°C

   

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If you get a ticket for speeding, it is based on your average speed or instantaneous speed? Explain
bagirrra123 [75]

Answer:

Instantaneous speed

Explanation:

Usually the speed measuring guns are used to measure the speed at a certain instant, so the measured speed is instantaneous.

The average speed is determined by the expression final distance minus initial distance divided by time

v_{aver} =\frac{x_{f}- x_{i}}{t}

The instantaneous speed is determined in the same way as the average, but with the exception that the travel displacements are shorter (very close one each other).

5 0
3 years ago
At a waterpark, sleds with riders are sent along a slippery, horizontal surface by the release of a large, compressed spring. Th
jekas [21]

Answer:

2.2 m/s

Explanation:

<u>solution:</u>

To calculate change in stored energy at desired extension

ΔU = 1/2*k*(δx)^2

     = 1/2*3700*(0.37^2-0.180^2)

     = 201 N.m

use work energy theorem

ΔU = ΔK = 1/2*m*v^2 = 201

              = 2.2 m/s

<u>note:</u>

calculation maybe wrong but method is correct.

8 0
3 years ago
Read 2 more answers
A pencil rolls horizontally of a 1 meter high desk and lands .25 meters from the base of the desk. How fast was the pencil rolli
vovikov84 [41]

Answer: 0.55 m/s

Explanation:

This situation is related to projectile motion (also called parabolic motion), where the main equations are as follows:

x=V_{o} cos\theta t (1)

y=y_{o}+Vo sin \theta t + \frac{g}{2}t^{2} (2)

Where:

x=0.25 m is the horizontal displacement of the pencil

V_{o} is the pencil's initial velocity

\theta=0\° since we are told the pencil rolls <u>horizontally</u> before falling

t is the time since the pencil falls until it hits the ground

y_{o}=1 m  is the initial height of the pencil

y=0  is the final height of the pencil (when it finally hits the ground)

g=-9.8m/s^{2}  is the acceleration due gravity, always acting vertically downwards

Begining with (1):

x=V_{o} cos(0\°) t (3)

x=V_{o}t (4)

Finding t from (2):

0=1 m+ \frac{-9.8m/s^{2}}{2}t^{2} (5)

t=\sqrt{\frac{-2y_{o}}{g}} (6)

Substituting (6) in (4):

x=V_{o}\sqrt{\frac{-2y_{o}}{g}} (7)

Isolating V_{o}:

V_{o}=\frac{x}{\sqrt{\frac{-2y_{o}}{g}}} (8)

V_{o}=\frac{0.25 m}{\sqrt{\frac{-2(1 m)}{-9.8m/s^{2}}}} (9)

Finally:

V_{o}=0.55 m/s

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3 years ago
The force of replusion between two like charged particles will increase if​
Alex_Xolod [135]

Answer:

The distance of separation is decreased

Explanation:

From Cuolomb's law, we know that the strength of charge is inversely proportional to the distance of separation between the charges. To mean that increasing the distance let's say from 2m to 3 m would mean initial strength getting form 1/4 to 1/9 which is a decrease. The vice versa is true hence the force of repulsion can increase only when we decrease the distance of separation.

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Describe one situation in which forces are created&gt;
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If the measurement is in joules then you can push something or pull something as long as you are moving the object. Formula: f*n force times newtons
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