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Lady_Fox [76]
3 years ago
13

Anna pushes a box with a force of 8.00 newtons. She generates a power of 3.00 watts. How much time does it take for Anna to move

the box the distance of 9.72 meters?
Physics
2 answers:
QveST [7]3 years ago
8 0
Power is the energy in a system per time.  It will have units of Watts which is equal to joules per second. It can be expressed as:

P = E / t

where E = Force x distance

P = Fd / t
t = Fd / P
t = 8 (9.72) / 3.0
t = 25.92 s
Ratling [72]3 years ago
8 0

Answer:

time taken, t = 25.92 seconds

Explanation:

It is given that,

Force acting on the box, F = 8 N

Power generated on the box, P = 3 watts

Distance traveled by the box, d = 9.72 m

We know that the power generated by an object is equal to the total work done divided by total time taken. Its formula is given by :

P=\dfrac{W}{t}

Since, W = F d

P=\dfrac{Fd}{t}

t=\dfrac{Fd}{P}

t=\dfrac{8\ N\times 9.72\ m}{3\ W}

t = 25.92 seconds

So, the time taken by Anna to move the box to the distance of 9.72 meters is 25.92 seconds. Hence, this is the required solution.

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Explanation:

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3 0
3 years ago
How does a 12-month lunar calendar differ from our 12-month solar calendar?.
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2 years ago
A car accelerates at a rate of 13m/s^2[S]. If the car's initial velocity is 120km/h[N]. What will its final velocity be in m/s,
Delvig [45]

Answer:

the final velocity of the car is 59.33 m/s [N]

Explanation:

Given;

acceleration of the car, a = 13 m/s²

initial velocity of the car, u = 120 km/h = 33.33 m/s

duration of the car motion, t = 2 s

The final velocity of the car in the same direction is calculated as follows;

v = u + at

where;

v is the final velocity of the car

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6 0
2 years ago
(1 point) A pilot flies in a straight path for 1 hour and 30 min. She then makes a course correction, heading 10 degrees to the
kati45 [8]

Answer:

The pilot is 2214.22 miles from her starting position

Explanation:

Since the pilot is traveling at a constant speed of 635 mph, the total distance traveled can be easily found as follows:

1stleg: d_{1} = 1.5*635 = 952.5 mi\\2ndleg: d_{2} = 2*635 = 1270 mi

There was a 10 degrees deviation, so the angle between the trajectory of both legs is 170 degrees.

The distance we need to find is that from the start of the first leg to the end of the second leg, those three distances form a triangle and since the side we're interested in is opposite to the 170 degrees angle, we can determine its length by the law of cosines:

d_{3}^{2} =d_{1}^{2} + d_{2}^{2} -2*d_{1}*d_{2}*cos(170)\\d_{3}^{2} =952.5^{2} + 1270^{2} -2*952.5*1270*cos(170)\\d_{3}=2214.22mi

The pilot is 2214.22 miles from her starting position

8 0
2 years ago
What are the signs of the velocity, force, and acceleration (components) afterthe cart is released and is moving qway from the m
SVETLANKA909090 [29]

Answer:

car is moving away its direction is negative.

the speed must also be negative.

speed this distance decreases the acceleration is negative and if the speed is increasing the acceleration is positive.

Explanation:

In the exercise they indicate that the direction to the motion sensor is positive, as they indicate that the car is moving away its direction is negative.

The speed of the car is

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As the positions are negative, and the car moves away the speed must also be negative.

The analysis for acceleration must be very careful if the speed this distance decreases the acceleration is negative and if the speed is increasing the acceleration is positive.

3 0
2 years ago
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