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gayaneshka [121]
2 years ago
8

What would decrease the gravitational pull between the sun and Earth?(1 point)

Physics
1 answer:
VARVARA [1.3K]2 years ago
3 0

The gravitational pull between the sun and Earth decreases if the sun was farther away from the earth.

<h3>What is Gravitational Force?</h3>

Any two bodies' gravitational pull on one another is directly proportional to the product of their masses and inversely proportional to the square of their distance from one another.

How do the planets move in relation to the Sun? The planets' orbits around the Sun are maintained by the gravity of the Sun. The Moon orbits the Earth due to the Earth's gravitational pull on the Moon for the same reason. But if the Earth is being drawn to the Sun, why doesn't it fall into it or the Moon strike the Earth?

The cause of this is because Earth moves at a speed that is perpendicular to the Sun's gravitational pull. The planets are thus kept in their designated orbits by the Sun's attraction as well as their sideways motion. Similar to how the Earth orbits the Moon, the Moon does so without touching it.

F=G(M1M2)/R² where,

F denotes gravitational force between two bodies,

R is the distance between two bodies from their center,

M1 denotes mass of first body and,

M2 denotes mass of second body.

So according to the question, if the distance between two bodies will increase, then the gravitational force between them will also decrease.

Hence, if the sun was farther away from earth, then gravitational pull between the sun and earth will decrease.

To get more information about Gravitational force :

brainly.com/question/12528243

#SPJ1

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Twist-on connectors without the spring-steel coils (plastic threads only) are suitable for making branch-circuit connections.
Gnoma [55]

Answer:

if it is a plastic connector it wont work but if there is metal or steel it will work

Explanation:

6 0
3 years ago
A rigid tank contains nitrogen gas at 227 °C and 100 kPa gage. The gas is heated until the gage pressure reads 250 kPa. If the a
aleksley [76]

Answer:

 T₂ =602  °C

Explanation:

Given that

T₁ = 227°C =227+273 K

T₁ =500 k

Gauge pressure at condition 1 given = 100 KPa

The absolute pressure at condition 1 will be

P₁ = 100 + 100 KPa

P₁ =200 KPa

Gauge pressure at condition 2 given = 250 KPa

The absolute pressure at condition 2 will be

P₂ = 250 + 100 KPa

P₂ =350 KPa

The temperature at condition 2 = T₂

We know that

\dfrac{T_2}{T_1}=\dfrac{P_2}{P_1}\\T_2=T_1\times \dfrac{P_2}{P_1}\\T_2=500\times \dfrac{350}{200}\ K\\

T₂ = 875 K

T₂ =875- 273 °C

T₂ =602  °C

5 0
4 years ago
Which data set has the smallest standard deviation?
777dan777 [17]
The answer would be B.
<span>
Standard deviation basically measures how spread out the values are. Without solving, you can easily tell which one among your choices have a smaller deviation. The closer the values are to each other the smaller the standard deviation. The values of choice B are the closest together, so you can assume that they have the smallest standard deviation. </span>
8 0
4 years ago
Read 2 more answers
The end point of a spring oscillates with a period of 2.0 s when a block with mass m is attached to it. When this mass is increa
Nostrana [21]

Answer: The end point of a spring oscillates with a period of 2.0 s when a block with mass m is attached to it. When this mass is increased by 2.0 kg, the period is found to be 3.0 s.  Then the mass m is 0.625kg.

Explanation: To find the answer, we need to know more about the simple harmonic motion.

<h3>What is simple harmonic motion?</h3>
  • A particle is said to execute SHM, if it moves to and fro about the mean position under the action of restoring force.
  • We have the equation of time period of a SHM as,

                                          T=2\pi \sqrt{\frac{m}{k} }

  • Where, m is the mass of the body and k is the spring constant.
<h3>How to solve the problem?</h3>
  • Given that,

               T_1=2s\\m_1=m\\m_2=m+2kg\\T_2=3s

  • We have to find the value of m,

              T_1=2\pi \sqrt{\frac{m}{k} } \\T_2=2\pi \sqrt{\frac{m+2}{k} } \\\frac{T_1}{T_2} =\sqrt{\frac{m}{m+2} }\\\frac{2}{3} =\sqrt{\frac{m}{m+2} }\\\\

               m=\frac{5}{8} =0.625kg

Thus, we can conclude that, the mass m will be 0.625kg.

Learn more about simple harmonic motion here:

brainly.com/question/28045110

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3 0
2 years ago
The speed that light travels :
OLga [1]
I think it might be C.
4 0
3 years ago
Read 2 more answers
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