an experiment is conducted to compare 3 equally spaced dryer temperatures on fabric shrinkage. the researcher samples 15 pieces
1 answer:
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Answer:
M₂ = M then L₂ = L
M₂> M then L₂ = \frac{M}{M_{2}} L
Explanation:
This is a static equilibrium exercise, to solve it we must fix a reference system at the turning point, generally in the center of the rod. By convention counterclockwise turns are considered positive
∑ τ = 0
The mass of the rock is M and placed at a distance, L the mass of the rod M₁, is considered to be placed in its center of mass, which by uniform e is in its geometric center (x = 0) and the triangular mass M₂, with a distance L₂
The triangular shape of the second object determines that its mass can be considered concentrated in its geometric center (median) that tapers with a vertical line if the triangle is equilateral, the most used shape in measurements.
M L + M₁ 0 - m₂ L₂ = 0
M L - m₂ L₂ = 0
L₂ = L
From this answer we have several possibilities
* if the two masses are equal then L₂ = L
* If the masses are different, with M₂> M then L₂ = \frac{M}{M_{2}} L
Initially jet is moving horizontally
so we know that
now we have
PART a)
Net horizontal force is given as
Part b)
since the acceleration in vertical direction is zero
so as per Newton's law we know
PART c)
speed of the jet increases in vertical direction from ZERO to 21 m/s in 20 seconds and speed increases in horizontal direction from 95 m/s from 80 m/s in same time
vertical acceleration
horizontal acceleration
now net horizontal force will be
PART d)
Now for vertical force we have
PART e)
Now after reaching the cruising level the horizontal speed becomes constant and in vertical direction speed decrease to ZERO from 21 m/s in 13 s
So we have
now we have horizontal force as
Part f)