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Kitty [74]
3 years ago
6

Which object has the least amount of kinetic energy? a car driving down a road a soccer ball rolling down a hill a bicycle locke

d to a bike rack a satellite orbiting Earth
Physics
2 answers:
Schach [20]3 years ago
8 0

Answer:

A bicycle locked to a bike

Explanation:

The kinetic energy of an object when an object is moving. The mathematical expression for the kinetic energy of an object is given by :

KE=\dfrac{1}{2}mv^2

Where

m is the mass of an object

v is the velocity of an object

First option : A car driving down a road, the car is moving i.e. it will possess kinetic energy.

Second option : A soccer ball rolling down a hill, the ball is moving i.e. it will possess kinetic energy

Third option : A bicycle locked to a bike, neither bicycle nor bike is moving i.e. it will not possess kinetic energy.

Fourth option : A satellite orbiting Earth, the satellite is moving i.e. it will possess kinetic energy.

Hence, "a bicycle locked to a bike " has least amount of kinetic energy.

mars1129 [50]3 years ago
7 0
<span> a bicycle locked to a bike rack im pretty sure</span>
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A car moving at 44 km/ h skids 16 m with locked brakes. How far will the car skid with locked brakes at 110km/ h
svp [43]

Answer:

100 m

Explanation:

44 km/h = 12.2 m/s

110 km/h = 30.6 m/s

Given:

Δx = 16 m

v₀ = 12.2 m/s

v = 0 m/s

Find: a

v² = v₀² + 2aΔx

(0 m/s)² = (12.2 m/s)² + 2a (16 m)

a = -4.67 m/s²

Given:

v₀ = 30.6 m/s

v = 0 m/s

a = -4.67 m/s²

Find: Δx

v² = v₀² + 2aΔx

(0 m/s)² = (30.6 m/s)² + 2 (-4.67 m/s²) Δx

Δx = 100 m

7 0
3 years ago
At what angle (relative to the horizontal) should a curve 52 m in radius be banked if no friction is required to prevent the car
velikii [3]

Answer:

Banking angle, \theta=15.77^{\circ}

Explanation:

It is given that,

Radius of the curve, r = 52 m

Speed of the car, v = 12 m/s

Acceleration due to gravity, g=9.8\ m/s^2

Let the curved is banked at an angle of \theta with respect to the horizontal. It is given by :

tan\theta=\dfrac{v^2}{rg}

tan\theta=\dfrac{(12)^2}{52\times 9.8}                

\theta=15.77^{\circ}

So, the curve is banked at an angle of 15.77 degrees wrt the horizontal. Hence, this is the required solution.

7 0
3 years ago
The magnetic bearing of compass "north" is _____. 090 180 270 360
MrMuchimi
In navigation bearing refers to : 1. the direction of motion itself; 2. the direction of a distant object relative to the current course 3.the angle away from North of a distant point as observed at the current point.

There is a thing called absolute bearing, and it refers to the angle between the magnetic North/true North and an object. (e.g. an object of 0 degrees would be dead ahead, whereas and object of 180 degrees would be behind you)
6 0
3 years ago
A circular loop of radius 11.7 cm is placed in a uniform magnetic field. (a) If the field is directed perpendicular to the plane
Mama L [17]

Answer:

Magnetic field, B = 0.199 T

Explanation:

It is given that,

Radius of circular loop, r = 11.7 cm = 0.117 m

Magnetic flux through the loop, \phi=8.6\times 10^{-3}\ T/m^2

The magnetic flux linked through the loop is :

\phi=B.A

\phi=BA\ cos\theta

Here, \theta=0

B=\dfrac{\phi}{A}

or

B=\dfrac{\phi}{\pi r^2}

B=\dfrac{8.6\times 10^{-3}}{\pi (0.117 )^2}

B = 0.199 T

So, the strength of the magnetic field is 0.199 T. Hence, this is the required solution.

4 0
3 years ago
What is the magnitude of the force a 25 charge exerts on a 3 mc charge 35cm away?
lara31 [8.8K]
The electrostatic force between two charges is given by
F=k_e  \frac{q_1 q_2}{r^2}
where
ke is the Coulomb's constant
q1 and q2 are the two charges
r is the separation between the charges

In our problem, 
q_1 = 25 \mu C=25 \cdot 10^{-6} C
q_2 = 3 mC = 3 \cdot 10^{-3} C
r=35 cm=0.35 m
Therefore the electrostatic force is
F=(8.99 \cdot 10^9 Nm^2C^{-2}) \frac{(25 \cdot 10^{-6}C)(3 \cdot 10^{-3}C)}{(0.35 m)^2}= 5510 N
4 0
4 years ago
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