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maria [59]
3 years ago
12

Is the following equation balanced? 2Al + 3NiBr2 AlBr3 + 3Ni yes no

Physics
2 answers:
Oliga [24]3 years ago
8 0

Answer:

No-the equation is not balanced.

Explanation:

The balanced equation will be;

2Al + 3NiBr2→ 2AlBr3 + 3Ni

According to the law of conservation of mass, the mass of reactants should always be the same as the mass of the products in a chemical equation.

Therefore, the number of atoms of each element in a chemical equation should always be the same on both sides of the equation, that is the side of reactants and side of products.

Balancing of chemical equations ensures that the number of atoms of each element is equal in both sides of the equation

jeka943 years ago
5 0
<h3><u>Answer;</u></h3>

<u>No-</u>the equation is not balanced.

<h3><u>Explanation;</u></h3>
  • The balanced equation will be;

<em>2Al + 3NiBr2→ 2AlBr3 + 3Ni</em>

  • <em><u>According to the law of conservation of mass, the mass of reactants should always be the same as the mass of the products in a chemical equation. </u></em>
  • Therefore, the number of atoms of each element in a chemical equation should always be the same on both sides of the equation, that is the side of reactants and side of products.
  • <em><u>Balancing of chemical equations ensures that the number of atoms of each element is equal in both sides of the equation</u></em>.
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What difficulty will you encounter if you only have data from two recording station?
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iron ball weight 400 gram inside water when it is completely impressed in water 53 gram water is displaced what will be the weig
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2 years ago
The wavelength of visible light is about 5500 times longer than the wavelength of x-rays. If you represent the wavelenth of an x
Pie

Answer:

458.33 ft

Explanation:

We are given that

Wavelength of of an x- ray photon=1 in

Wavelength of of an x- ray photon==\frac{1}{12}ft

1 in=\frac{1}{12}feet

We have to find the  length of line (in feet) drawn by you to represent the wavelength of visible light.

According to question

Wavelength of visible light=5500\times \frac{1}{12} ft

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Find the average energy E for (a) An n-state system, in which a given state can have energy 0,,2,...,n . (b) A harmonic oscillat
kicyunya [14]

Answer:

a♦1  E_average = n E₀ / 2 , b) E_average= infinity

Explanation:

The energy values ​​form an arithmetic series, whose sum is

          S = n (a₁ + aₙ) / 2 = n (2a₁ + (n-1) r)/ 2

Where n is the number of terms, a₁ is the first term, aₙ the last term and r is the difference between two consecutive numbers in the series

          r = 2E₀ - 0 = 2E₀

Therefore the sum is

       S = n (0 + n E₀) / 2

      S = n² E₀ / 2

     

The average value is

         E_average = S / n

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b) the case of harmonic oscillation

We have two possibilities.

- if we take a finite number and terms gives the same previous value

- If we take an infinite number of fears the series gives infinity and the average is also infinite

          E_average= infinity

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3 years ago
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