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maria [59]
3 years ago
12

Is the following equation balanced? 2Al + 3NiBr2 AlBr3 + 3Ni yes no

Physics
2 answers:
Oliga [24]3 years ago
8 0

Answer:

No-the equation is not balanced.

Explanation:

The balanced equation will be;

2Al + 3NiBr2→ 2AlBr3 + 3Ni

According to the law of conservation of mass, the mass of reactants should always be the same as the mass of the products in a chemical equation.

Therefore, the number of atoms of each element in a chemical equation should always be the same on both sides of the equation, that is the side of reactants and side of products.

Balancing of chemical equations ensures that the number of atoms of each element is equal in both sides of the equation

jeka943 years ago
5 0
<h3><u>Answer;</u></h3>

<u>No-</u>the equation is not balanced.

<h3><u>Explanation;</u></h3>
  • The balanced equation will be;

<em>2Al + 3NiBr2→ 2AlBr3 + 3Ni</em>

  • <em><u>According to the law of conservation of mass, the mass of reactants should always be the same as the mass of the products in a chemical equation. </u></em>
  • Therefore, the number of atoms of each element in a chemical equation should always be the same on both sides of the equation, that is the side of reactants and side of products.
  • <em><u>Balancing of chemical equations ensures that the number of atoms of each element is equal in both sides of the equation</u></em>.
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Answer:

Option B. O because the net force was 5 N in Alfredo's direction

Explanation:

To know the the correct answer to the question given above, we shall determine the net force acting on the bat. This can be obtained as follow:

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From the calculation made above, we can see that the net force is 5N in Alfredo's direction. This is the reason why Alfredo end up having the bat.

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Answer:

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Explanation:

The question above is related to "Newton's Law of Motion." According to the <em>Third Law of Motion</em>, whenever an object exerts a force on another object <em>(action force)</em>, an equal force is exerted against it. This force is of the same magnitude but opposite direction.

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