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maria [59]
3 years ago
12

Is the following equation balanced? 2Al + 3NiBr2 AlBr3 + 3Ni yes no

Physics
2 answers:
Oliga [24]3 years ago
8 0

Answer:

No-the equation is not balanced.

Explanation:

The balanced equation will be;

2Al + 3NiBr2→ 2AlBr3 + 3Ni

According to the law of conservation of mass, the mass of reactants should always be the same as the mass of the products in a chemical equation.

Therefore, the number of atoms of each element in a chemical equation should always be the same on both sides of the equation, that is the side of reactants and side of products.

Balancing of chemical equations ensures that the number of atoms of each element is equal in both sides of the equation

jeka943 years ago
5 0
<h3><u>Answer;</u></h3>

<u>No-</u>the equation is not balanced.

<h3><u>Explanation;</u></h3>
  • The balanced equation will be;

<em>2Al + 3NiBr2→ 2AlBr3 + 3Ni</em>

  • <em><u>According to the law of conservation of mass, the mass of reactants should always be the same as the mass of the products in a chemical equation. </u></em>
  • Therefore, the number of atoms of each element in a chemical equation should always be the same on both sides of the equation, that is the side of reactants and side of products.
  • <em><u>Balancing of chemical equations ensures that the number of atoms of each element is equal in both sides of the equation</u></em>.
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A suspension bridge has twin towers that are 1300 feet apart. Each tower extends 180 feet above the road surface. The cables are
zhannawk [14.2K]

Answer:

y = 17.04 ft

Explanation:

Since the cable touches the road at the mid point of two towers

so here we have vertex at that mid point taken to be origin

now the maximum height on the either side is given as

y = 180 ft

horizontal distance of the tower from mid point is given as

x = \frac{1300}{2} = 650 ft

now from the equation of parabola we have

y = k x^2

180 = k(650^2)

k = 4.26 \times 10^{-4}

now we have

y = (4.26 \times 10^{-4})x^2

now we need to find the height at distance of 200 ft from center

so we have

y = (4.26 \times 10^{-4})(200^2)

y = 17.04 ft

8 0
3 years ago
In most cases, what happens to a liquid when it cools?
erik [133]

Answer:

Option (A) and (F)

Explanation:

As the liquid cools down, it means the temperature decreases the density of the liquid increases in most o the cases.

Now the volume is inversely proportional to the density of substance so density increases.

7 0
3 years ago
Which of the following quantities is inversely proportional to the gravitational pull between two objects?
Contact [7]

Answer:

C

Explanation:

Since gravitational force is inversely proportional to the square of the separation distance between the two interacting objects, more separation distance will result in weaker gravitational forces

I hope this helps a little bit

7 0
2 years ago
Read 2 more answers
The local high school is installing new bleachers at the stadium and must also add handrails to meet code. The students know the
Advocard [28]

Answer:

The handrails must be approximately 10.63 meters long

Explanation:

The given parameters are;

The height of the bleachers, h = 8 m

The depth of the bleachers, d = 7 m

The length of the hand rails to go along the bleachers from bottom to top is given by Pythagoras' Theorem as follows;

The length of the hand rail = √(d² + h²)

∴ The length of the hand rail = √(7² + 8²) = √113 ≈ 10.63

In order for the handrails to go along the bleachers from top to bottom, they must be approximately 10.63 meters long.

5 0
3 years ago
If both of these balls are traveling down a bowling lane at the SAME speed, which one would would have more kinetic energy?
Mariana [72]
<h2>Answer:</h2>

<u>Ball A has more kinetic energy</u>

<h2>Explanation:</h2>

As we know that Kinetic energy is given by

K. E = 1/2 mv²

Since K E is dependent upon both mass and velocity so increasing mass will produce more kinetic energy if the speed remains constant

As the mass of ball A is greater than ball B so we can say that the kinetic energy of ball is more than ball B


3 0
3 years ago
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