Complete question:
A solenoid that is 98.6 cm long has a cross-sectional area of 24.3 cm2. There are 1310 turns of a wire carrying a current of 6.75 A. (a) Calculate the energy density of the magnetic field inside the solenoid. (b) Find the total energy stored in the magnetic field there (neglect end effects).
Answer:
(a) the energy density of the magnetic field inside the solenoid is 50.53 J/m³
(b) the total energy stored in the magnetic field is 0.121 J
Explanation:
Given;
length of the solenoid, L = 98.6 cm = 0.986 m
cross-sectional area of the solenoid, A = 24.3 cm² = 24.3 x 10⁻⁴ m²
number of turns of the solenoid, N = 1310 turns
The magnitude of the magnetic field inside the solenoid is given by;
B = μ₀nI
B = μ₀(N/L)I
Where;
μ₀ is permeability of free space, = 4π x 10⁻⁷ m/A

(a) Calculate the energy density of the magnetic field inside the solenoid

(b) Find the total energy stored in the magnetic field
U = uV
U = u (AL)
U = 50.53 (24.3 x 10⁻⁴ x 0.986)
U = 0.121 J
Power = Work/time
Work= energy
Potential energy =mxgxh
Power=mxgxh/t
Power=68x10x7/9
Power=529 watts
Answer:
A
Explanation:
traveling north no displacement ,west displacement is 10,
<h2>
It takes 0.867 seconds to get to the top of its motion</h2>
Explanation:
We have equation of motion v = u + at
Initial velocity, u = 8.5 m/s
Final velocity, v = 0 m/s - At maximum height
Time, t = ?
Acceleration , a = -9.81 m/s²
Substituting
v = u + at
0 = 8.5 + -9.81 x t
t = 0.867 s
It takes 0.867 seconds to get to the top of its motion
Something must be wrong in the data you have, since this is basic using of linear motion's formulas.
vf=v0+at. Where vf= final velocity; v0= initial velocity, a=acceleration and t=time.
If the rocket is initially at rest, v0=0. Therefore vf=at. Plugging numbers in gives 445=99*4.5, However
445≠445.5.
Check it and then calculate the distance from x=a*t^2.