Solution :
Given weight of Kathy = 82 kg
Her speed before striking the water,
= 5.50 m/s
Her speed after entering the water,
= 1.1 m/s
Time = 1.65 s
Using equation of impulse,

Here, F = the force ,
dT = time interval over which the force is applied for
= 1.65 s
dP = change in momentum
dP = m x dV
![$= m \times [V_f - V_o] $](https://tex.z-dn.net/?f=%24%3D%20m%20%5Ctimes%20%5BV_f%20-%20V_o%5D%20%24)
= 82 x (1.1 - 5.5)
= -360 kg
∴ the net force acting will be


= 218 N
Answer:
d) What is the force if we doubled both the masses AND we doubled the distance
I’m going to use molasses as an example of a substance.
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The size or amount of a material/substance does not affect its density.
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The wind will blow from higher pressure over the water to lower pressure over the land causing sea breeze. <span>The </span>sea breeze<span> strength will vary depending on the temperature difference </span>between<span> the </span>land<span> and the ocean</span>