How much force does it take to accelerate a 2,000-kg car at 4 m/s
1 answer:
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Answer:
the static charge is not always distributed on the surface of the conductor, there are also charges in the volume but of lesser magnitude
Explanation:
In this hypothetical system the electric force is of type
F =
in this case the force decays to zero much faster,
if we call Fo the force of Coulomb's law
F₀ =
assuming the constant k is the same
the relationship between the two forces is
F / F₀ = 1 / r
F = F₀ / r
when analyzing this expression the force decays much faster to zero.
In an electric conductor, charges of the same sign may not feel any repulsive force from other charges that are at a medium distance, so there is a probability that some charges are distributed in the volume of the material, this does not happen with coulomb's law
Consequently, the static charge is not always distributed on the surface of the conductor, there are also charges in the volume but of lesser magnitude