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2 years ago

Explain what it means when we say a substance is magnetic. That is type of substance which produce magnetic field

Physics

1 answer:

Ostrovityanka [42]2 years ago

6 0

<h3><u>Answer;</u></h3>

A substance that is magnetic is a substance that can generate or produce magnetic field

<h3><u>Explanation;</u></h3>

Magnetic substances generate magnetic field since they have atoms or molecules that have unpaired electrons.
Magnetic materials may be either paramagnetic or ferromagnetic. Paramagnetic materials are materials such as aluminium in which become magnetized in a magnetic field but their magnetism disappears upon the removal of magnetic field.
Ferromagnetic materials are materials such as nickel and iron which can reatin their magnetic properties even when magnetic field is removed.

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Wat would happen if a feather and a ball were released from the same height at the same time? Gravity Experiments for Kids – Sci

solniwko [45]

Answer:

They would land at the same time

Explanation:

They would land at the same exact time.

As weird, impossible and unbelievable as it appears. When in a vacuum, every weight, body and material when released from the same height would land on the ground at the same time. This also means that like in the question, a feather and a ball would land at the same time. And just for illustrations as well, a feather and a car would land at the same time as well.

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3 years ago

Which sentence uses the correct form of the verb choose?

MrRa [10]

Answer:

The answer is B

Explanation:

It's past tense and dad is singular

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2 years ago

Read 2 more answers

A stationary boat in the ocean is experiencing waves from a storm. The waves move at 59 km/h and have a wavelength of 145 m . Th

krek1111 [17]

Answer:

The time elapses until the boat is first at the trough of a wave is 4.46 seconds.

Explanation:

Speed of the wave, v = 59 km/h = 16.38 m/s

Wavelength of the wave, $\lambda=145\ m$

If f is the frequency of the wave. The frequency of a wave is given by :

$v=f\lambda\\\\f=\dfrac{v}{\lambda}\\\\f=\dfrac{16.38\ m/s}{145\ m}\\\\f=0.112\ Hz$

The time period of the wave is given by :

$T=\dfrac{1}{f}\\\\T=\dfrac{1}{0.112\ Hz}\\\\T=8.92\ s$

We need to find the time elapses until the boat is first at the trough of a wave. So, the time will be half of the time period of the wave.

$T=\dfrac{8.92}{2}\\\\T=4.46\ s$

Hence, this is the required solution.

5 0

3 years ago

Only the sun and other stars in space generate these kinds of waves:

Reika [66]

Answer:

<h2>Ultraviolet Waves.</h2>

Explanation:

The Sun emits waves called "Solar Waves", which have a wavelengths between 160 and 400 nanometers. According to the electromagnetic spectrum, these waves are defined as Ultraviolet, which have a frequency around the order of $10^{16}$ , which is really intense and high energy.

Therefore, the answer is Ultraviolet Waves.

6 0

3 years ago

"Determine the magnitude of the net force of gravity acting on the Moon during an eclipse when it is directly between Earth and

spayn [35]

Answer:

Net force = 2.3686 × 10^(20) N

Explanation:

To solve this, we have to find the force of the earth acting on the moon and the force of the sun acting on the moon and find the difference.

Now, from standards;

Mass of earth;M_e = 5.98 × 10^(24) kg

Mass of moon;M_m = 7.36 × 10^(22) kg

Mass of sun;M_s = 1.99 × 10^(30) kg

Distance between the sun and earth;d_se = 1.5 × 10^(11) m

Distance between moon and earth;d_em = 3.84 × 10^(8) m

Distance between sun and moon;d_sm = (1.5 × 10^(11)) - (3.84 × 10^(8)) = 1496.96 × 10^(8) m

Gravitational constant;G = 6.67 × 10^(-11) Nm²/kg²

Now formula for gravitational force between the earth and the moon is;

F_em = (G × M_e × M_m)/(d_em)²

Plugging in relevant values, we have;

F_em = (6.67 × 10^(-11) × 5.98 × 10^(24) × 7.36 × 10^(22))/(3.84 × 10^(8))²

F_em = 1.9909 × 10^(20) N

Similarly, formula for gravitational force between the sun and moon is;

F_sm = (G × M_s × M_m)/(d_sm)²

Plugging in relevant values, we have;

F_se = (6.67 × 10^(-11) × 1.99 × 10^(30) ×

7.36 × 10^(22))/(1496.96 × 10^(8))²

F_se = 4.3595 × 10^(20) N

Thus, net force = F_se - F_em

Net force = (4.3595 × 10^(20) N) - (1.9909 × 10^(20) N) = 2.3686 × 10^(20) N

8 0

2 years ago