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lisov135 [29]
1 year ago
12

which one of these represent total momentum of a system of two particles traveling one against the other?

Physics
1 answer:
antoniya [11.8K]1 year ago
5 0

The total momentum of a system is the vector sum of all the individual masses that comprise the system.

Moreover, To calculate the total momentum of two objects during a collision, add their individual momentums. You can calculate the momentum for each object using the formula p=mv, where p is the momentum, m is the mass, and v is the velocity. The law of conservation of momentum can be expressed as follows. For a collision between object 1 and object 2 in an isolated system, the total momentum of the two objects before the collision is equal to the total momentum of the two objects after the collision.

You can learn more about this at:

brainly.com/question/20301772#SPJ4

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A syrup added to an empty container with a mass of 115.25g . When 0.100 pint of syrup is added, the total mass of the container
sesenic [268]
<span>Density is a physical property of a substance that represents the mass of that substance per unit volume. It is a property that can be used to describe a substance. We calculate as follows:

Density = 182.48 g - 115.25 g / 0.100 pint ( 0.47 L / 1 pint ) = 67.23 g/0.047L
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3 0
3 years ago
What is the net force on an object when you combine a force of 10n north with a force of 5n south?
svetoff [14.1K]
Let north as positive
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7 0
3 years ago
Consider a wave along the length of a stretched slinky toy, where the distance between coils increases and decreases. What type
GrogVix [38]

Answer:

"Longitudinal wave" is the appropriate answer.

Explanation:

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3 0
3 years ago
Read 2 more answers
A 1640 kg merry-go-round with a radius of 7.50 m accelerates from rest to a rate of 1.00 revolution per 8.00 s. Estimate the mer
son4ous [18]

Solution :

Given data :

Mass of the merry-go-round, m= 1640 kg

Radius of the merry-go-round, r = 7.50 m

Angular speed, $\omega = \frac{1}{8}$  rev/sec

                             $=\frac{2 \pi \times 7.5}{8}$  rad/sec

                              = 5.89 rad/sec

Therefore, force required,

$F=m.\omega^2.r$

   $$=1640 \times (5.89)^2 \times 7.5  

   = 427126.9 N

Thus, the net work done for the acceleration is given by :

W = F x r

   = 427126.9 x 7.5

   = 3,203,451.75 J

6 0
3 years ago
I'm sorry if any one seen that post about me saying I'm done with life and I don't want to be here it was my little cuzin @vicky
solniwko [45]
I did not see the post. But if she actually needs help She can dm me. keep y'all's head up❤
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3 years ago
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