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natulia [17]
1 year ago
10

A 25kg child resting at the top of a 2 meter slide has how much potential energy?

Physics
1 answer:
levacccp [35]1 year ago
3 0

Potential energy of a child at the top is 490 J.

Potential energy, U = mgh

U = potential energy

m  = mass of an object, given = 25kg

g = acceleration due to gravity, given = 9.8 m/s^{2}

h = height of an object, given = 2 meter

Put the values in potential energy formula, U = mgh

U = mgh

U = 25 × 9.8 × 2

U = 490 J

Hence, Potential energy of a child at the top is 490 J.

Potential energy is the  type of energy, which is product of mass of an object, acceleration due to gravity and height of an object where it is placed. Its S.I. unit is joule and is represented by J.

Learn more about potential energy here:- brainly.com/question/14427111

#SPJ1

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irga5000 [103]

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3 years ago
A camera is equipped with a lens with a focal length of 34 cm. When an object 2.4 m (240 cm) away is being photographed, what is
puteri [66]

Answer:

The magnification is -6.05.

Explanation:

Given that,

Focal length = 34 cm

Distance of the image =2.4 m = 240 cm

We need to calculate the distance of the object

\dfrac{1}{u}+\dfrac{1}{v}=\dfrac{1}{f}

Where, u = distance of the object

v = distance of the image

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Put the value into the formula

\dfrac{1}{u}=\dfrac{1}{34}-\dfrac{1}{240}

\dfrac{1}{u}=\dfrac{103}{4080}

u =\dfrac{4080}{103}

The magnification is

m = \dfrac{-v}{u}

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m = -6.05

Hence, The magnification is -6.05.

6 0
3 years ago
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Sidana [21]
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5 0
4 years ago
What is the magnitude and direction (right or left) of the
Sunny_sXe [5.5K]

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Explanation:

If we calculate the net force acting on the box, we will have:

<u>In y-component:</u>

Fy_{net}=F_{n}+F_{g} (1)

Where F_{n}=12 N is the Normal force, directed upwards and F_{g}=-12 N is the weight of the box (gravity force), directed downwards.

Fy_{net}=12 N-12 N (2)

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Fx_{net}=-3 N + 15 N (5)

Fx_{net}=12 N (6) This is the net force in the horizontal component

Therefore, the total net force acting on the box is 12 N directed to the right

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VMariaS [17]
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