A 25kg child resting at the top of a 2 meter slide has how much potential energy?
1 answer:
Potential energy of a child at the top is 490 J.
Potential energy, U = mgh
U = potential energy
m = mass of an object, given = 25kg
g = acceleration due to gravity, given = 9.8 m/
h = height of an object, given = 2 meter
Put the values in potential energy formula, U = mgh
U = mgh
U = 25 × 9.8 × 2
U = 490 J
Hence, Potential energy of a child at the top is 490 J.
Potential energy is the type of energy, which is product of mass of an object, acceleration due to gravity and height of an object where it is placed. Its S.I. unit is joule and is represented by J.
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Explanation:
The 11Ω, 22Ω, and 33Ω resistors are in parallel. That combination is in series with the 4Ω and 10Ω resistors.
The net resistance is:
R = 4Ω + 10Ω + 1/(1/11Ω + 1/22Ω + 1/33Ω)
R = 20Ω
Using Ohm's law, we can find the current going through the 4Ω and 10Ω resistors:
V = IR
120 V = I (20Ω)
I = 6 A
So the voltage drops are:
V = (4Ω) (6A) = 24 V
V = (10Ω) (6A) = 60 V
That means the voltage drop across the 11Ω, 22Ω, and 33Ω resistors is:
V = 120 V − 24 V − 60 V
V = 36 V
So the currents are:
I = 36 V / 11 Ω = 3.27 A
I = 36 V / 22 Ω = 1.64 A
I = 36 V / 33 Ω = 1.09 A
If we wanted to, we could also show this using Kirchhoff's laws.
