Question

Block X and Y are attached to each other by a light rope and can slide along a horizontal

Answer 1

the action-reaction forces that the blocks exert on each other will 13 N and 22N

Force on a Horizontal Plane

Force is the product of mass and acceleration. There will be constant acceleration on both object X and Y.

Given that the Mass of block X is 10 kg and that of block Y is 5 kg. The magnitude of force of friction on blocks X and Y is 8.0 N and 4.0 N respectively. if an applied force of 40 N [right] acts on block,

We are given that:

• Mass of block X = 10 Kg

• Mass of block Y = 5 Kg

• Applied force = 40 N

• Magnitude of friction on X block = 8N

• Magnitude of friction on Y block = 4 N

With the use of the formula below,

F - $F_{r}$ = ma

Where

• F = force applied

• $F_{r}$ = frictional force

• m = mass

• a = acceleration

The acceleration will be;

40 - (8 + 4) = (10 + 5)a

40 - 12 = 15 a

28 = 15a

a = 28/15

a = 1.8667 m/$s^{2}$

The tension between the two blocks will be

Force applied-frictional force on X-tension = mass of X × acceleration

That is,

F - $F_{r}$ = ma

40-8-T = 10 × 1.8667

32 - T = 18.667

T = 32 - 18.667

T = 13.33 N

The opposite reaction will be

F - 8 = 10 x 1.8667

F - 4 = 18.67

F = 18.67 + 4

F = 22.67 N

Therefore, the action-reaction forces that the blocks exert on each other will 13 N and 22N

Learn more about forces here: brainly.com/question/388851

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