All categories

2 years ago

Block X and Y are attached to each other by a light rope and can slide along a horizontal

Physics

1 answer:

Tresset [83]2 years ago

8 0

the action-reaction forces that the blocks exert on each other will 13 N and 22N

<h3>Force on a Horizontal Plane</h3>

Force is the product of mass and acceleration. There will be constant acceleration on both object X and Y.

Given that the Mass of block X is 10 kg and that of block Y is 5 kg. The magnitude of force of friction on blocks X and Y is 8.0 N and 4.0 N respectively. if an applied force of 40 N [right] acts on block,

We are given that:

Mass of block X = 10 Kg

Mass of block Y = 5 Kg

Applied force = 40 N

Magnitude of friction on X block = 8N

Magnitude of friction on Y block = 4 N

With the use of the formula below,

F - $F_{r}$ = ma

Where

F = force applied

$F_{r}$ = frictional force

m = mass

a = acceleration

The acceleration will be;

40 - (8 + 4) = (10 + 5)a

40 - 12 = 15 a

28 = 15a

a = 28/15

a = 1.8667 m/ $s^{2}$

The tension between the two blocks will be

Force applied-frictional force on X-tension = mass of X × acceleration

That is,

F - $F_{r}$ = ma

40-8-T = 10 × 1.8667

32 - T = 18.667

T = 32 - 18.667

T = 13.33 N

The opposite reaction will be

F - 8 = 10 x 1.8667

F - 4 = 18.67

F = 18.67 + 4

F = 22.67 N

Therefore, the action-reaction forces that the blocks exert on each other will 13 N and 22N

Learn more about forces here: brainly.com/question/388851

#SPJ1

You might be interested in

Suzy drops a rock from the roof of her house. Mary sees the rock pass her 2.9 m tall window in 0.134 sec. From how high above th

timama [110]

Answer:

Explanation:

Given

length of window $h=2.9\ m$

time Frame for which rock can be seen is $\Delta t=0.134\ s$

Suppose h is height above which rock is dropped

Time taken to cover $h+2.9 is t_1$

so using equation of motion

$y=ut+\frac{1}{2}at^2$

where y=displacement

u=initial velocity

a=acceleration

t=time

time taken to travel h is

$h=0+0.5\times g\times (t_2)^2---2$

Subtract 1 and 2 we get

$2.9=0.5g(t_1^2-t_2^2)$

$5.8=g(t_1+t_2)(t_1-t_2))$

and from equation $t_1-t_2=0.134\ s$

so $t_1+t_2=\frac{5.8}{9.8\times 0.134}$

$t_1+t_2=4.416\ s$

and $t_1=t_2+\Delta t$

so $t_2+\Delta t+t_2=4.416$

$2t_2+0.134=4.416$

$t_2=0.5\times 4.282$

$t_2=2.141\ s$

substitute the value of $t_2$ in equation 2

$h=0.5\times 9.8\times (2.141)^2$

$h=22.46\ m$

8 0

3 years ago

When a sideways force acts on a moving object, what effect does it have?

My name is Ann [436]

Answer:

it makes the object speed increase, decrease and change the direction of the object.

Hope it helps!

6 0

3 years ago

A lead ball is dropped into a lake from a diving board 5.0 m above the water. After entering the water, it sinks to the bottom w

nirvana33 [79]

Answer:

$|D_{depth} |=19.697m$

Explanation:

To find Depth D of lake we must need to find the time taken to hit the water.So we use equation of simple motion as:

Δx=vit+(1/2)at²

$x_{f}-x_{i}=v_{i}t+(1/2)at^{2}\\ -5.0m=(o)t+(1/2)(-9.8m/s^{2} )t^{2}\\ -4.9t^{2}=-5.0\\ t^{2}=5/4.9\\t=\sqrt{1.02} \\t=1.01s$

As we have find the time taken now we need to find the final velocity vf from below equation as

$v_{f}=v_{i}+at\\v_{f}=0+(-9.8m/s^{2} )(1.01s) \\v_{f}=-9.898m/s$

So the depth of lake is given by:

first we need to find total time as

t=3.0-1.01 =1.99 s

$|D_{depth} |=|vt|\\|D_{depth} |=|(-9.898m/s)(1.99s)|\\|D_{depth} |=19.697m$

6 0

3 years ago

Which of the following statements is true about conductors and insulators? Select all that apply.

ra1l [238]

Conductors have many free electrons
insulators have few free electrons
conductors are ideal for electrical wiring

6 0

3 years ago

Read 2 more answers

An athlete with mass m running at speed v grabs a light rope that hangs from a ceiling of height H and swings to a maximum heigh

-Dominant- [34]

Answer:

d) The 2 athletes reach the same height, because the athletes run with the same speed.

Explanation:

In the whole process , kinetic energy is converted into potential energy .

1/2 m v² = mgh

v² = 2gh

h = v² / 2g

In this expression we see that height attained does not depend upon mass of the object . At the same time it also makes it clear that it depends upon velocity . As the velocity in both the cases are same , height attained by both of them will be same. Hence option d ) is correct.

7 0

3 years ago