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goldenfox [79]
3 years ago
12

farmer produces two types of corn plants. one has larger sized kernels but fewer yields and another has smaller sized kernels wi

th high yield. he wants to produce a corn plant with larger sized kernels with high yield.which of these methods would be applicable for this?eliminate the gene for lesser yield from the genome of larger sized kernels and eliminate the gene for smaller sized kernels from the other corn variety.insert the genome responsible for larger sized kernels into the gene of the corn with smaller sized kernels and a high yield.insert the gene responsible for larger sized kernels into the genome of the corn with smaller sized kernels and a high yield.
Biology
1 answer:
vekshin13 years ago
5 0
The answer is: insert the gene responsible for larger sized kernels into the genome of the corn with smaller sized kernels and a high yield.<span>

The techniques of genetic engineering are used to introduce hybrid genes for some desired substance or trait into the genome of other organisms. Here, the desired trait is larger sized kernels. So, the gene responsible for this trait will be inserted into the genome of the corn </span><span>with smaller sized kernels and a high yield.

It should be taken into consideration why two other choices are not correct:
1. there are no genes for less or more of something in the genome.
2. genes are part of a genome, so the genome for a trait cannot be inserted into a gene of an organism.</span>
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Assuming the genes are not linked nor interacting with each other, the expected number of long stemmed plants with purple flowers, producing wrinkled peas, L-P-rr, is 288.

<h3>Available data</h3>

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  • purple flowers are dominant to white,
  • round peas are dominant to wrinkled

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  • A heter0zyg0us plant is self-crossed
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Cross) heter0zyg0us plant is self-crossed

Parental) LlPpRr

Gametes) LPR, LPr, LpR, Lpr, lPR, lPr, lpR, lpr

Assuming that these genes are not linked nor interacting with each other, to make the calcs easier we will make crosses considering each gene separately.

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Parental) Ll  x  Ll

F1) 1/4 LL, 2/4 Ll, 1/4 ll

     <u>3/4 long stem,</u> 1/4 short stem

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Parental) Pp  x  Pp

F1) 1/4 PP, 2/4 Pp, 1/4 pp

     <u>3/4 purple flowers</u>, 1/4 white flowers

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Parental) Rr  x  Rr

F1) 1/4 RR, 2/4 Rr, 1/4 rr

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Now, we will get the proportion of individuals with long stems, purple flowers, producing wrinkled peas, L-P-rr

<u><em>Note</em></u><em>: The symbol - is representing either a dominant or a recessive allele.</em>

From the crosses, we know that

  • 3/4 are long stemmed,
  • 3/4 have purple flowers, and
  • 1/4 have wrinkled peas.

To get the proportion of individuals expressing all these traits together, we just need to multiply these values.

3/4 L- x 3/4 P- x 1/4 rr =<u> 9/64 L-P-rr</u>

Knowing that  the total number of plants is 2,048 and that there are 64 possible gametes combinations from this cross, we will use the proportion 9/64 to get the number of plants with these traits.

64 ------------- 2,048 plants

9 -------------- X = (9 x 2048) / 64 = 288 plants.

<em>We expect to find 288 long stemmed plants with purple flowers, producing wrinkled peas.</em>

<em />

<em />

You will learn more about trihybrid crosses at

brainly.com/question/21942441

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