Answer:
78
Step-by-step explanation:
Answer:
should have multiplied both x and 2 by 3.
3x + 6
Step-by-step explanation:
a) mode = 3 ( cause most number of car that have 3 teachers)
b) median = 3 (1,1,1,2,2,2,2,3,3,3,3,3,3,4,4) the middle position)
c) mean = (1*3 + 2*4 +3*6 + 4*2)/15 = 2.467(average)
So Volume (V) of a sphere is:
![V = \frac{4}{3} \pi {r}^{3}](https://tex.z-dn.net/?f=V%20%3D%20%20%5Cfrac%7B4%7D%7B3%7D%20%5Cpi%20%7Br%7D%5E%7B3%7D%20)
so essentially we need to divide the machine's Volume (V) the gumball volume (v)
![V = \frac{4}{3} \pi {r}^{3} = \frac{4}{3} \pi {(6)}^{3} \\ V = \frac{4}{3}(216) \pi = 288\pi](https://tex.z-dn.net/?f=V%20%3D%20%20%5Cfrac%7B4%7D%7B3%7D%20%5Cpi%20%7Br%7D%5E%7B3%7D%20%20%3D%20%5Cfrac%7B4%7D%7B3%7D%20%5Cpi%20%7B%286%29%7D%5E%7B3%7D%20%20%5C%5C%20V%20%3D%20%20%5Cfrac%7B4%7D%7B3%7D%28216%29%20%5Cpi%20%20%3D%20288%5Cpi)
![v = \frac{4}{3} \pi {( \frac{1}{3} )}^{3} = \frac{4}{3} \times \frac{1}{27} \pi \\ v = \frac{4}{81} \pi](https://tex.z-dn.net/?f=v%20%3D%20%20%5Cfrac%7B4%7D%7B3%7D%20%5Cpi%20%7B%28%20%5Cfrac%7B1%7D%7B3%7D%20%29%7D%5E%7B3%7D%20%20%3D%20%20%5Cfrac%7B4%7D%7B3%7D%20%5Ctimes%20%20%5Cfrac%7B1%7D%7B27%7D%20%20%5Cpi%20%20%5C%5C%20v%20%3D%20%20%5Cfrac%7B4%7D%7B81%7D%20%5Cpi)
now we divide V by v:
![V/v = \frac{288\pi}{ \frac{4\pi}{81} } = \frac{288}{1} \times \frac{81}{4} = 5832](https://tex.z-dn.net/?f=V%2Fv%20%3D%20%20%5Cfrac%7B288%5Cpi%7D%7B%20%5Cfrac%7B4%5Cpi%7D%7B81%7D%20%7D%20%20%3D%20%20%5Cfrac%7B288%7D%7B1%7D%20%20%5Ctimes%20%20%5Cfrac%7B81%7D%7B4%7D%20%20%3D%205832)
so b) 5,832 gumballs can fit in the machine
Answer:
f(2) = 0 and f(6) = -4
Step-by-step explanation:
First, find f(x) when x = 2
Plug in 2 as x in the function:
f(x) = -(x - 2)
f(2) = -(2 - 2)
f(2) = -(0)
f(2) = 0
Next, find f(x) when x = 6. Plug in 6 as x in the function:
f(x) = -(x - 2)
f(6) = -(6 - 2)
f(6) = -(4)
f(6) = -4
So, f(2) = 0 and f(6) = -4