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arlik [135]
3 years ago
15

Calculate the wavelength in centimeters of radar energy at a frequency of 10 GHz. What is the frequency in gigahertz of radar en

ergy at a wavelength of 25 cm
Physics
1 answer:
ddd [48]3 years ago
8 0

Answer:

Energy will be equal to 6.6\times 10^{-27}J

Frequency will be equal to 12\times 10^8Hz

Explanation:

We have given frequency of the radar f = 10 GHz =10\times 10^6Hz

Speed of light c=3\times 10^8m/sec

Plank's constant h=6.6\times 10^{-34}js

So energy E=h\nu,here h is plank's constant and \nu is frequency

So energy E=6.6\times 10^{-34}\times 10^{7}=6.6\times 10^{-27}J

In second case we have given wavelength = 25 cm = 0.25 m

Wavelength is equal to \lambda =\frac{c}{f}

So f=\frac{c}{\lambda }=\frac{3\times 10^8}{0.25}=12\times 10^8Hz

So frequency will be equal to 12\times 10^8Hz

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Which list places different units of matter in the correct sequence from largest to smallest
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What do you mean?

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A swimmer of mass 64.38 kg is initially standing still at one end of a log of mass 237 kg which is floating at rest in water. He
nikklg [1K]

Answer:

0.9432 m/s

Explanation:

We are given;

Mass of swimmer;m_s = 64.38 kg

Mass of log; m_l = 237 kg

Velocity of swimmer; v_s = 3.472 m/s

Now, if we consider the first log and the swimmer as our system, then the force between the swimmer and the log and the log and the swimmer are internal forces. Thus, there are no external forces and therefore momentum must be conserved.

So;

Initial momentum = final momentum

m_l × v_l = m_s × v_s

Where v_l is speed of the log relative to water

Making v_l the subject, we have;

v_l = (m_s × v_s)/m_l

Plugging in the relevant values, we have;

v_l = (64.38 × 3.472)/237

v_l = 0.9432 m/s

8 0
3 years ago
2. Suppose your car has a maximum braking acceleration of -5 m/s2. Calculate the stopping distance for an initial speed of 25 m/
Hitman42 [59]

Answer:

s=62.5m

Explanation:

Use the equation v²=u²+2as, where v is the final velocity, u is the initial velocity, a is the acceleration and s is the distance.

0²=25²+2(-5)s

10s=625

s=62.5m

3 0
3 years ago
A 100-g toy car moves along a curved frictionless track. At first, the car runs along a flat horizontal segment with an initial
aleksandrvk [35]

Answer:

The final velocity of the car is 2.02 m/s

Explanation:

Hi there!

The kinetic energy of the car as it runs along the first flat horizontal segment can be calculated using the following equation:

KE = 1/2 · m · v²

Where:

KE =  kinetic energy

m = mass

v = velocity

Then, the initial kinetic energy will be:

KE = 1/2 · 0.100 kg · (2.77 m/s)²

KE = 0.384 J

When the car gains altitude, it gains potential energy. The amount of gained potential energy will be equal to the loss of kinetic energy. So let´s calculate the potential energy of the car as it reaches the top:

PE = m · g · h

Where:

PE = potential energy.

m = mass

g = acceleration due to gravity.

h = height.

PE = 0.100 kg · 9.8 m/s² · 0.184 m

PE = 0.180 J

Then, the final kinetic energy will be (0.384 J - 0.180 J) 0.204 J

Using the equation of kinetice energy, we can obtain the velocity of the car:

KE =  1/2 · m · v²

0.204 J = 1/2 · 0.100 kg · v²

2 · 0.204 J  / 0.100 kg = v²

v = 2.02 m/s

The final velocity of the car is 2.02 m/s

7 0
3 years ago
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