A, convection, is your answer
Answer:
0.9432 m/s
Explanation:
We are given;
Mass of swimmer;m_s = 64.38 kg
Mass of log; m_l = 237 kg
Velocity of swimmer; v_s = 3.472 m/s
Now, if we consider the first log and the swimmer as our system, then the force between the swimmer and the log and the log and the swimmer are internal forces. Thus, there are no external forces and therefore momentum must be conserved.
So;
Initial momentum = final momentum
m_l × v_l = m_s × v_s
Where v_l is speed of the log relative to water
Making v_l the subject, we have;
v_l = (m_s × v_s)/m_l
Plugging in the relevant values, we have;
v_l = (64.38 × 3.472)/237
v_l = 0.9432 m/s
Answer:
s=62.5m
Explanation:
Use the equation v²=u²+2as, where v is the final velocity, u is the initial velocity, a is the acceleration and s is the distance.
0²=25²+2(-5)s
10s=625
s=62.5m
Answer:
The final velocity of the car is 2.02 m/s
Explanation:
Hi there!
The kinetic energy of the car as it runs along the first flat horizontal segment can be calculated using the following equation:
KE = 1/2 · m · v²
Where:
KE = kinetic energy
m = mass
v = velocity
Then, the initial kinetic energy will be:
KE = 1/2 · 0.100 kg · (2.77 m/s)²
KE = 0.384 J
When the car gains altitude, it gains potential energy. The amount of gained potential energy will be equal to the loss of kinetic energy. So let´s calculate the potential energy of the car as it reaches the top:
PE = m · g · h
Where:
PE = potential energy.
m = mass
g = acceleration due to gravity.
h = height.
PE = 0.100 kg · 9.8 m/s² · 0.184 m
PE = 0.180 J
Then, the final kinetic energy will be (0.384 J - 0.180 J) 0.204 J
Using the equation of kinetice energy, we can obtain the velocity of the car:
KE = 1/2 · m · v²
0.204 J = 1/2 · 0.100 kg · v²
2 · 0.204 J / 0.100 kg = v²
v = 2.02 m/s
The final velocity of the car is 2.02 m/s