Strategy: with the measures you can determine the volume of the plate of aluminum. Then you can use the density of aluminum to calculate the mass.
With the mass of aluminum and its atomic mass you can find the number of moles and thereafter the number of atoms.
Finally divide the cost by the number of atoms to find the cost of one single atom.
Let's do it.
Volume of aluminum plate, V: 0.0112 in* 4.83 in* 2.60 in * [2.54 cm/in]^3 = 2.305 cm^3
Density of aluminum (from Wikipedia), d = 2.70 g/cm^3
mass, m = d*V = 2.305 cm^3 * 2.70 g/ cm^3 = 6.22 g
Atomic mass of aluminum (from Wikipedia), am = 27 g / mol
Number of moles, n = m/am = 6.22 g / 27 g / mol = 0.23 mol
Number of atoms = n*Avogadro constant = 0.23 mol * 6.022 * 10^23 atoms/mol = 1.39*10^23
Cost per atom = cost of the can / number of atoms =$ 0.05 /1.39*10^23 atoms = 3.60 * 10^ - 25 $/atom
The question is incomplete, the complete question is;
Consider the following reaction at 298K.
2 H+(aq) + 2 Cr2+(aq) =H2(g) + 2 Cr3+(aq)
Which of the following statements are correct?
Choose all that apply.
K > 1
ΔGo < 0
Eocell < 0
n = 2 mol electrons
The reaction is reactant-favored.
Answer:
K > 1
ΔGo < 0
n = 2 mol electrons
Explanation:
If we look at the reaction; 2 H+(aq) + 2 Cr2+(aq) -----> H2(g) + 2 Cr3+(aq), we will notice that the reaction is a spontaneous reaction because E°cell= 0-(-0.41) = 0.41 V
If the reaction is a spontaneous electrochemical process, we expect it to be product favoured with K>1. Also, a spontaneous reaction must have ∆G<0.
Lastly, we can see that two electrons were transferred according to the balanced equation for the electrochemical reaction.
What makes people wanna come us with these things
Answer:
the answer is pH of 7 I don't no Hydrochloric hijinx work
Density can be calculated using the following rule:
density = mass / volume
Therefore,
volume = mass / density
For diamond:
we have mass = 0.5 grams and density = 3.51 g / cm^3
Substituting in the rule, we can calculate the volume of diamond as follows:
volume = 0.5 / 3.51 = 0.14245 cm^3
For graphite:
we have mass = 0.5 grams and density = 2.25 g / cm^3
Substituting in the rule, we can calculate the volume of graphite as follows:
volume = 0.5 / 2.25 = 0.2223 cm^3
