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ra1l [238]
3 years ago
11

Suppose you have a crystal composed of elements X and Y in which the radius ratio is approximately ½, so that the sodium chlorid

e lattice is possible. Each ion is about the same size as Na+ and Cl-, respectively, but each ion is doubly charged X++ and Y--. Would XY (s) have a higher or lower melting point than NaCl (s)?
Chemistry
1 answer:
WINSTONCH [101]3 years ago
7 0

Answer:

XY would have a higher melting point than NaCl.

Explanation:

The electrostatic force (F) between ions in an ionic lattice can be estimated using Coulomb's Law.

F=k.\frac{q_{1}.q_{2}}{r^{2} }

where,

k is the Coulomb's constant

q₁ and q₂ are the charges of the ions

r is the distance between the ions

X⁺⁺ and Y⁻⁻ are doubly charged with respect to Na⁺ and Cl⁻ so the force between them is 4 times the force between Na⁺ and Cl⁻. Since the force is stronger, it would require more energy to break it to take it to the liquid state, so a higher melting point is expected.

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Answer:

31,536,000 seconds

Explanation:

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germanium -66 has a half-life of 2.5 hours. you have 35 grams of radioactive material. after 16 days, how much radioactive mater
Maru [420]

Hey there!

A half-life means after a certain amount of time, half of that substance will be gone/changed after that time.

How many half-lives are in 16 days?

Multiply 16 by 24 (to get the total hours) and divide that by 2.5.

That is 153.6 half-lives.

35(0.5)^(153.6) represents the equation for this.

Simplify this and get 8.88 x 10^(-45).

There will be 2.02 x 10^(-45)g of germanium-66 sample remaining after 16 days.

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6 0
3 years ago
Which atom loses 2 electrons while forming an ion?
BabaBlast [244]

Answer:

it would be a cation ... i believe

Explanation:

To become a cation, a positively charged ion, an atom would have to lose at least two electrons  

7 0
3 years ago
A solution contains 72.0 g of HCI and 468 g of (C6H6). what is the mole fraction of benzene
erica [24]
<span>Molar mass (MM) of benzene C6H6
C = 6 * 12 = 72u
H = 6 * 1 = 6u
MM C6H6 = 72 + 6 = 78 g / mol
Benzene - Molar Mass = 78 g --------- 1 mol
Of A Mix has 468 g -------------- x

78x = 468
X = 468/78
X = 6 moles
 
Molar mass (MM) of Hydrochloric Acid HCl H = 1 * 1 = 1u
CI = 1 * 35 = 35u
MM HCl = 1 + 35 = 36 g / mol
 
Hydrochloric Acid - Molar Mass = 36 g ---------- 1 mol
Of A Mix has 72 g ------------ y

36y = 72
Y = 72/36
Y = 2 moles
 
Thus, a mixture has a total of 8 moles (6 mol + 2 mol).
Dividing One Mole Amount of Each Substance by the Number of Total Mole Amounts, Then we will obtain a Molar Fraction of Each:
Molar fraction make benzene = (6/8) simplify 2 = 3/4
Molar Fraction to make Hydrochloric Acid = (2/8) = simplify 2 = 1/4

Note:. The sum of the molar fractions of the always give goes 1, we have: 3/4 + 1/4 = 1
 

ANSWER: 
</span>\boxed{\frac{3}{4}}
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