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mars1129 [50]
2 years ago
5

Round to 4 significant figures. 35.5450

Chemistry
2 answers:
IrinaVladis [17]2 years ago
8 0

Answer:

no sé m i e r d a ..............

Explanation:

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nsnnznsnnsnndnndnnmnnndndbdsjssnssnnsjssnsnssnnnnsnwkssksksskssdhditzgzyxyxtkzjtxtkztzktzittiztjkTjTustuitigtihlhktiylYOrufuoxyljzgkzhlKzyklzylzkkKKkKKkJjjjBjjjjsjsjsiskskssssss</u></em><em><u>esnsksnsnnznsnnsnndnndnnmnnndndbdsjssnssnnsjssnsnssnnnnsnwkssksksskssdhditzgzyxyxtkzjtxtkztzktzittiztjkTjTustuitigtihlhktiylYOrufuoxyljzgkzhlKzyklzylzkkKKkKKkJjjjBjjjjsjsjsiskskssssss</u></em><em><u>esnsksnsnnznsnnsnndnndnnmnnndndbdsjssnssnnsjssnsnssnnnnsnwkssksksskssdhditzgzyxyxtkzjtxtkztzktzittiztjkTjTustuitigtihlhktiylYOrufuoxyljzgkzhlKzyk</u></em><em><u>esnsksnsnnznsnnsnndnndnnmnnndndbdsjssnssnnsjssnsnssnnnnsnwkssksksskssdhditzgzyxyxtkzjtxtkztzktzittiztjkTjTustuitigtihlhktiylYOrufuoxyljzgkzhlKzyklzylzkkKKkKKkJjjjBjjjjsjsjsiskskssssss</u></em><em><u>esnsksnsnnznsnnsnndnndnnmnnndndbdsjssnssnnsjssnsnssnnnnsnwkssksksskssdhditzgzyxyxtkzjtxtkztzktzittiztjkTjTustuitigtihlhktiylYOrufuoxyljzgkzhlKzyklzylzkkKKkKKkJjjjBjjjjsjsjsiskskssssss</u></em><em><u>lzylzkkKKkKKkJjjjBjjjjsjsjsiskskssssss</u></em><em><u>esnsksnsnnznsnnsnndnndnnmnnndndbdsjssnssnnsjssnsnssnnnnsnwkssksksskssdhditzgzyxyxtkzjtxtkztzktzittiztjkTjTustuitigtihlhktiylYOrufuoxyljzgkzhlKzyklzylzkkKKkKKkJjjjBjjjjsjsjsiskskssssss</u></em><em><u>esnsksnsnnznsnnsnndnndnnmnnndndbdsjssnssnnsjssnsnssnnnnsnwkssksksskssdhditzgzyxyxtkzjtxtkztzktzittiztjkTjTustuitigtihlhktiylYOrufuoxyljzgkzhlKzyklzylzkkKKkKKkJjjjBjjjjsjsjsiskskssssss</u></em></h2>
bulgar [2K]2 years ago
6 0

My answer to the question is 35.55.

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A calorimeter contains 100 g of water at 39.8 ºC. A 8.23 g object at 50 ºC is placed inside the calorimeter. When equilibrium ha
Tju [1.3M]
When equilibrium has been reached so, according to this formula we can get the specific heat of the unknown metal and from it, we can define the metal as each metal has its specific heat:

Mw*Cw*ΔTw = Mm*Cm*ΔTm

when 
Mw → mass of water
Cw → specific heat of water
ΔTw → difference in temperature for water 

Mm→ mass of metal
Cw→ specific heat of the metal
ΔTm → difference in temperature for metal

by substitution:

100g * 4.18 * (40-39.8) = 8.23 g * Cm * (50-40)

∴ Cm = 83.6 / 82.3 = 1.02 J/g.°C

when the Cm of the Magnesium ∴ the unknown metal is Mg
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3 years ago
1. Lithium, water, edible salt, chalk, Carbon, Lime, Nitrogen, Potassium, Oxygen,
Kaylis [27]

Answer:

Explanation:

An atom is the smallest unit of an element that can take part in a chemical reaction. Atoms (and there corresponding symbols) mentioned in the question are

Lithium ⇒ Li

Carbon ⇒ C

Nitrogen ⇒ N

Potassium ⇒ K

Oxygen ⇒ O

Iron ⇒ Fe

Chlorine ⇒ Cl

A compound is substance that contains two or more atoms that are chemically combined and can be represented with a chemical formula. The compounds (and there corresponding formula) mentioned in the question are

Water ⇒ H₂O

Edible salt (sodium chloride) ⇒ NaCl

Chalk (calcium carbonate) ⇒ CaCO₃

Lime (calcium oxide) ⇒ CaO

Iodides (such as sodium iodide and potassium iodide) ⇒ NaI and KI respectively

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Name the type of equation shown here: 2NaBr+Ca(OH)2 —&gt;CaBr2+2NaOH
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A) Double replacement
Because the reactants switch when they become products
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2 years ago
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PLZ HELP For the reaction: 2NO2(g) → N2O4(l),
Furkat [3]

Answer: \Delta H_{rxn}=-20kJ/mol-(+66kJ/mol)

Explanation:

Heat of reaction or enthalpy change is the energy released or absorbed during the course of the reaction.

It is calculated by subtracting the enthalpy of reactants from the enthalpy of products.

\Delta H=H_{products}-H_{reactants}

\Delta H = enthalpy change = ?

H_{products} = enthalpy of products

H_{reactants} = enthalpy of reactants

For the given reaction :

2NO_2(g)\rightarrow N_2O_4(l)

\Delta H=H_{N_2O_4}-2\times H_{NO_2}

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6 0
3 years ago
What is the molar mass of KOH?
Julli [10]
<h3>Answer:</h3>

56.11 g/mol

<h3>General Formulas and Concepts:</h3>

<u>Math</u>

<u>Pre-Algebra</u>

Order of Operations: BPEMDAS

  1. Brackets
  2. Parenthesis
  3. Exponents
  4. Multiplication
  5. Division
  6. Addition
  7. Subtraction
  • Left to Right<u> </u>

<u>Chemistry</u>

<u>Atomic Structure</u>

  • Reading a Periodic Table
<h3>Explanation:</h3>

<u>Step 1: Define</u>

[Compound] KOH

<u>Step 2: Identify</u>

[PT] Molar Mass of K - 39.10 g/mol

[PT] Molar Mass of O - 16.00 g/mol

[PT] Molar Mass of H - 1.01 g/mol

<u>Step 3: Find</u>

39.10 + 16.00 + 1.01 = 56.11 g/mol

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2 years ago
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