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damaskus [11]
3 years ago
6

Based on the diagram of a ball rolling down hill, what statement is true? A) The ball in box C has less kinetic energy than the

ball in box B. B) The ball in box A has more kinetic energy than the ball in box B. C) The ball in box C has more potential energy than the ball in box B. D) The ball in box C has less potential energy than the ball in box B.
Physics
1 answer:
Gre4nikov [31]3 years ago
7 0

Answer:

Explanation:The sum of kinetic energy and potential energy is called mechanical energy.

The kinetic energy is possessed by an object by virtue of its motion and the potential energy is due to height of the object under the action of gravity.

Mathematically,

v is the velocity of the object

h is the height from ground

We know that the potential energy at topmost point is maximum and it is least at ground.

So, from the given figure it is clear that the ball in box C has less potential energy than the ball in box B.

Hence, the correct option is (d) "The ball in box C has less potential energy than the ball in box B".

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Dmitrij [34]

Answer:

the answer is neutrons and energy

8 0
3 years ago
A certain resistor dissipates 0.5 W when connected to a 3 V potential difference. When connected to a 1 V potential difference,
Stels [109]

Answer:

<h2>0.056 W</h2>

Explanation:

Power = IV

From ohms law we know that

V= IR\\\\I= \frac{V}{R} \\\\Power= \frac{V}{R}*V\\\\Power= \frac{V^2}{R}

Given data

P1 = 0.5 Watt

P2 = ?

V1= 3 Volts

V2= 1 Volt

Thus we can solve for the power dissipated as follows

P1= \frac{V1^2}{R1}\\\\P2= \frac{V2^2}{R2}

\frac{P1}{P2} = \frac{V1^2}{V2^2}\\\\ P2=\frac{ V2^2}{ V1^2} *P1\\\\ P2=\frac{ 1^2}{ 3^2} *0.5= 0.055= 0.056 W

<em>The  resistor will dissipate 0.056 Watt</em>

7 0
3 years ago
You're carrying a 3.2-m-long, 24kg pole to a construction site when you decide to stop for a rest. You place one end of the pole
Aleksandr [31]

Answer:

Tension of 132N

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We need to apply Summatory of Force to find the tension in the hand.

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\sum F = 24(9.8)

F_1 + F_2= 24(9.8)

We apply summatory of moments then

F_2*1.25 = F_1*1.6

Where the Force 2 is 1.25m from the center of summatory,

We can note that,

1.6 m - 0.35m=1.25m

We have two equation and two incognites, then replacing (1) in (2)

1.6(235.2 -F_2) = 1.25F_2

376.32 = F2(1.6+1.25)

F_2= \frac{376.32}{2.85}

F_2 =132 N

5 0
3 years ago
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3 years ago
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