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MAXImum [283]
1 year ago
3

During a baseball game, a batter hits a high

Physics
1 answer:
Katena32 [7]1 year ago
7 0

The ball rises 53.361 m above the point where the bat hit the ball.

When a batter hits a ball high in a baseball game, the ball remains in the air for 6.6 seconds.

The acceleration of gravity is 9.8 m/s².

The vertex value of time is half of 6.6 seconds or 3.3 seconds.

Therefore, the final velocity at the maximum height is v = 0 m/s

Now, using the equation of motion:

v - u = gt

v = u + gt

u × sin(θ) = - gt

u × sin(θ) = 9.8 × 3.3

u × sin(θ) = 32.34 m/s

Now, by using the equation of motion:

v² - u² = 2gh

h = ( v² - u²) / 2g

h = ( 0 - (32.34)² ) / 2(9.8)

h = (1045.8756) / 19.6

h = 53.361 m

The ball rises 53.361 meter high.

Learn more about acceleration here:

brainly.com/question/460763

#SPJ9

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