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1 year ago

The light at an intersection is red and a police officer directs you to go through the intersection. what should you do?

1 answer:

7 0

Go through the intersection without stopping is the appropriate action to be taken in a case where the light at an intersection is red and a police officer directs you to go through it.

<h3>What is Traffic light?</h3>

This is also referred to as stoplights and is present in the intersection of roads etc so as to help control traffic and prevent the occurrences of accidents on the road.

In cases where there is no officer, the traffic light must be obeyed but where the officer is present then his authority overrules and must be obeyed as he is in the best position to know the reason why the traffic light should be ignored in this type of scenario.

This is therefore the reason why the individual should go through the intersection without stopping.

Read more about Traffic light here brainly.com/question/28033780

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Depict the following path: You drive 14 blocks East, 7 blocks North, and 2 blocks West. Use the vertex of the graph (coordinates

horrorfan [7]

Answer:

Displacement = $12\hat{i} +7\hat{j}$

Magnitude of displacement = 13.89 units

Angle of displacement = 30.26°

Explanation:

Mark the co-ordinates of each of the end points of the vectors.

The marked co-ordinates are shown below.

Displacement is the shortest distance between two points. Here, displacement between the starting and end points is the vector $\overrightarrow{OA}$ .

Displacement vector for a point A $(x,y)$ from origin O is given as:

$\overrightarrow{OA}=(x-0)\hat{i}+(y-0)\hat{j}$

Magnitude is given as:

$|\overrightarrow{OA}|=\sqrt{x^{2}+y^{2}}$

Direction of the vector is given as:

$\theta=tan^{-1}\frac{y}{x}$

Therefore, displacement vector is:

$\overrightarrow{OA}=(12-0)\hat{i}+(7-0)\hat{j}\\ \overrightarrow{OA}=12\hat{i}+7\hat{j}$

Magnitude of displacement is given as:

$|\overrightarrow{OA}|=\sqrt{x^{2}+y^{2}}\\ |\overrightarrow{OA}|=\sqrt{12^{2}+7^{2}}\\ |\overrightarrow{OA}|=\sqrt{144+49}\\\\ |\overrightarrow{OA}|=13.89$

Angle of displacement is:

$tan\theta=\frac{y}{x} =\frac{7}{12}\\\theta=tan^{-1}(\frac{7}{12})$

$\theta=30.26$ °

8 0

4 years ago

Find the weight required to stretch a steel road by 2 mm, if the length of the road is 2 m and diameter 4 mm. Y= 200 GPa and g -

svetlana [45]

Answer:

Option D is the correct answer.

Explanation:

We equation for elongation

$\Delta L=\frac{PL}{AE}$

Here we need to find weight required,

We need to stretch a steel road by 2 mm, that is ΔL = 2mm = 0.002 m

$A=\frac{\pi d^2}{4}=\frac{\pi ({4\times 10^{-3}})^2}{4}=1.26\times 10^{-5}m^2$

E = 200GPa = 2 x 10¹¹ N/m²

L=2m

Substituting

$0.002=\frac{P\times 2}{1.26\times 10^{-5}\times 2\times 10^{11}}\\\\P=2520N=256.4kg$

Option D is the correct answer.

6 0

3 years ago

Scientists review the work of other scientists to. . A) ensure the results are in agreement with accepted scientific beliefs. .

Masteriza [31]

Scientists review the work of other scientists to validate the results and check the evidence's reliability. The correct option among all the options that are given in the question is the fourth option or the last option or option "D". I hope that this is the answer that has come to your desired help.

7 0

3 years ago

Read 2 more answers

Not a question but need a lot of tips

skad [1K]

DibujaZos da buenos tips e incluso el pinta con colores faber castel son económicos y el dibujo queda epico

8 0

3 years ago

How much work was done by a hot air balloon to lift up a 100 Newton to a height of 300 meters?

Monica [59]

So, the work was done by that hot air-balloon is <u>30,000 J or 30 kJ</u>.

<h3>Introduction</h3>

Hi ! In this question, I will help you. <u>Work is the amount of force exerted to cause an object to move a certain distance from its starting point</u>. In physics, the amount of work will be proportional to the increase in force and increase in displacement. Amount of work can be calculated by this equation :

$\boxed{\sf{\bold{W = F \times s}}}$