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10 months ago

The light at an intersection is red and a police officer directs you to go through the intersection. what should you do?

1 answer:

7 0

Go through the intersection without stopping is the appropriate action to be taken in a case where the light at an intersection is red and a police officer directs you to go through it.

<h3>What is Traffic light?</h3>

This is also referred to as stoplights and is present in the intersection of roads etc so as to help control traffic and prevent the occurrences of accidents on the road.

In cases where there is no officer, the traffic light must be obeyed but where the officer is present then his authority overrules and must be obeyed as he is in the best position to know the reason why the traffic light should be ignored in this type of scenario.

This is therefore the reason why the individual should go through the intersection without stopping.

Read more about Traffic light here brainly.com/question/28033780

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An AM radio station broadcasts isotropically (equally in all directions) with an average power of 3.40 kW. A receiving antenna 6

lara [203]

To solve the problem we will apply the concepts related to the Intensity as a function of the power and the area, as well as the electric field as a function of the current, the speed of light and the permeability in free space, as shown below.

The intensity of the wave at the receiver is

$I = \frac{P_{avg}}{A}$

$I = \frac{P_{avg}}{4\pi r^2}$

$I = \frac{3.4*10^3}{4\pi(4*1609.34)^2} \rightarrow 1mile = 1609.3m$

$I = 6.529*10^{-6}W/m^2$

The amplitude of electric field at the receiver is

$I = \frac{E_{max}^2}{2\mu_0 c}$

$E_{max}= \sqrt{2I\mu_0 c}$

The amplitude of induced emf by this signal between the ends of the receiving antenna is

$\epsilon_{max} = E_{max} d$

$\epsilon_{max} = \sqrt{2I \mu_0 cd}$

Here,

I = Current

$\mu_0$ = Permeability at free space

c = Light speed

d = Distance

Replacing,

$\epsilon_{max} = \sqrt{2(6.529*10^{-6})(4\pi*10^{-7})(3*10^{8})(60.0*10^{-2})}$

$\epsilon_{max} = 0.05434V$

Thus, the amplitude of induced emf by this signal between the ends of the receiving antenna is 0.0543V

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3 years ago

A constant net force acts on an object. which of the following best describes the object's motion?

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The object<span> is moving with a decreasing acceleration. The </span>object<span> is moving with </span>a constant<span> velocity.</span>

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3 years ago

If a dog walks north for 10 meters and then east for 10 meters, what is the direction of its displacement?

Katyanochek1 [597]

The direction of its displacement wil be

c.northeast

In fact, the dog walks north for 10 meters and east for another 10 meters. The path of the dog can be represented with two vectors, A pointing north (of magnitude 10 meters) and B pointing east (of magnitude 10 meters). The direction of the resultant vector (due to east) will be given by

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$\theta=tan^{-1} (1)=45^{\circ}$

and the direction will be north-east.

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Because the temperature and the radiation are not correlated, they're not represented as functions of each other, they're represented as independent variables thus using graph 5 you cannot figure out how one affect another

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