<span> <span> <span> <span> CLIMATE: The amount of water in the air and the temperature of an area are both part of an area’s climate. Moisture speeds up chemical weathering. Weathering occurs fastest in hot, wet climates. It occurs very slowly in hot and dry climates. Without temperature changes, ice wedging cannot occur. In very cold, dry areas, there is little weathering. </span> <span> SURFACE AREA<span>-
Most weathering occurs on exposed surfaces of rocks and minerals. The more surface area a rock has, the more quickly it will weather. When a block is cut into smaller pieces, it has more surface area. So, therefore, the smaller pieces of a rock will weather faster than a large block of rock</span> </span> <span> ROCK COMPOSITION<span>-
Some minerals resist weathering. Quartz is a mineral that weathers slowly. Rocks made up of minerals such as feldspar, calcite, and iron, weather more quickly.</span> </span> <span> Pollution speeds up weathering. Factories and cars release carbon dioxide and other gases into the air. These gases dissolve in the rainwater, causing acid rain <span>to form. Acid rain contains nitric and sulfuric acid, causing rocks and minerals to dissolve faster. </span> </span> </span> </span> </span>
Answer:
v = 12.3 m / s
Explanation:
This is an exercise in kinetics in one dimension
v² = v₀² + 2 a x
In this exercise they tell us that the initial velocity is (v₀ = 13 m / s), the acceleration is a = -0.95 m / s2 and the distance x = 9.2 m
we substitute
v = √ (13 2 - 2 0.95 9.2)
v = 12.3 m / s
note that as the acceleration is negative the vehicle is stopping
The correct option is the first one, which is: N<span>egatively charged electrons.
</span>
J.J Thomson was British physicist who discovered the electron in 1897, by his experiment with "cathode ray tubes". For this work and contribution to science, he was awarded the Nobel Prize for physics in 1906.
Answer:
Explanation:
<u>Electric Resistance and Temperature
</u>
For some materials, resistivity is linearly related to the temperature. The function that relates them is
![R=R_o[1+\alpha (T-T_o)]](https://tex.z-dn.net/?f=R%3DR_o%5B1%2B%5Calpha%20%28T-T_o%29%5D)
Where Ro is the electric resistance at 20°C, 
is the temperature coefficient of the conductor, T is the actual temperature at which we want to compute R, and To is the initial temperature, usually 20°C.
The problem gives us the following values
Thus
![R=5[1+0.0004 (80-20)]=5.12\ \Omega](https://tex.z-dn.net/?f=R%3D5%5B1%2B0.0004%20%2880-20%29%5D%3D5.12%5C%20%5COmega)
