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1 year ago

which fossil fuel can be made to burn cleaner and reduce carbon dioxide emissions if it is combined with purified oxygen?

1 answer:

7 0

Fossil fuel can be made to burn cleaner and reduce carbon dioxide emissions if it is combined with purified oxygen is coal.

Coal can be made to burn cleaner and reduce the carbon dioxide it it will combine with the purified oxygen. coal is type of fossil fuel. coal is black in color or brownish black. the fossil fuel coal is made up of plant. the plant gets their energy from the sunlight so, it is clear that col is from sun. fossil fuels are non renewable source of energy.

Thus, Fossil fuel can be made to burn cleaner and reduce carbon dioxide emissions if it is combined with purified oxygen is coal.

To learn more about fossil fuel here

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If you have 4.01 g of H2, how many grams of NH3 can be produced?

stellarik [79]

Answer:

136.5886g of NH3

Explanation:

N2 + 3H2 = 2NH3

The mass of the N2 = 4.01

3H2 has a 2/1 ratio

This means the mass of 3H2 is twice as much as N2.

NH3= 2*N2 = 2*4.01 = 8.02 of NH3

Then, by multiplying the mass by MX (17.031)

8.02*17.031=136.5886g can be produced. Round it if needed.

8 0

3 years ago

For the reaction given below, the frequency factor A is 8.7 1012 s−1 and the activation energy is 63 kJ/mol. NO(g) + O3(g) → NO2

Alex73 [517]

Answer:

K(70°C) = 2213.376 s-1

Explanation:

balanced reaction:

NO(g) + O3(g) → NO2(g) + O2(g)

∴ Ea = 63 KJ/mol

∴ A = 8.7 E12 s-1

∴ T = 70°C ≅ 343 K

Arrhenius eq:

K(T) = Ae∧(- Ea/RT)

∴ R = 8.314 E-3 KJ/K.mol

⇒ K(70°C) = (8.7 E12 s-1)e∧[-(63)/(8.314 E-3)(343)]

⇒ K(70°C) = (8.7 E12 s-1)*(2.5444 E-10)

⇒ K(70°C) = 2213.376 s-1

6 0

3 years ago

Calculate Delta G for each reaction using Delta Gf values: answer kJ ...thank you

Leni [432]

Answer:

a) $\Delta G=2.6kJ$

b) $\Delta G=-979.57kJ$

c) $\Delta G=264.21kJ$

Explanation:

Hello,

In this case, in each reaction we must subtract the Gibbs free energy of formation the reactants to the Gibbs free energy of formation of the products considering each species stoichiometric coefficients. In such a way, the Gibbs free energy of formations are:

$\Delta _fG_{H_2}=\Delta _fG_{I_2}=0kJ/mol\\\Delta _fG_{HI}=1.3kJ/mol\\\Delta _fG_{CO_2}=-394.4kJ/mol\\\Delta _fG_{CO}=-137.3 kJ/mol\\\Delta _fG_{NH_3}=16.7 kJ/mol\\\Delta _fG_{HCl}=-95.3kJ/mol\\\Delta _fG_{MnO_2}=465.37kJ/mol\\\Delta _fG_{Mn}=0kJ/mol\\\Delta _fG_{NH_4Cl}=-342.81kJ/mol$

So we proceed as follows:

$\Delta G=2\Delta _fG_{HI}-\Delta _fG_{H_2}-\Delta _fG_{I_2}\\\\\Delta G=2*1.3\\\\\Delta G=2.6kJ$

$\Delta G=\Delta _fG_{Mn}+2*\Delta _fG_{CO_2}-\Delta _fG_{MnO_2}-2*\Delta _fG_{CO}\\\\\Delta G=0+2*-394.4-465.37-2*-137.3\\\\\Delta G=-979.57kJ$

$\Delta G=\Delta _fG_{NH_3}+\Delta _fG_{HCl}-\Delta _fG_{NH_4Cl}\\\\\Delta G=16.7-95.3-(-342.81)\\\\\Delta G=264.21kJ$

Regards.

6 0

3 years ago

For the reaction Cu2S(s)⇌2Cu+(aq)+S2−(aq)Cu2S(s)⇌2Cu+(aq)+S2−(aq), the equilibrium concentrations are as follows: [Cu+]=1.0×10−5

klio [65]

Answer:

1x10⁻¹²

Explanation:

Cu₂S(s) ⇌ 2Cu⁺(aq) + S²⁻(aq)

At equilibrium:

[Cu⁺] = 1.0x10⁻⁵ M

[S²⁻] = 1.0x10⁻² M

The equilibrium constant for the the reaction can be written as:

Keq = [Cu⁺]² * [S²⁻]

[Cu⁺] is squared because it has a stoichiometric coefficient of 2 in the reaction. <em>Cu₂S has no effect on the constant because it is a solid</em>.

Now we can <u>calculate the equilibrium constant</u>:

Keq = (1.0x10⁻⁵)² * 1.0x10⁻² = 1x10⁻¹²

8 0

3 years ago

The mass of a mole of carbon atoms is 12.011 grams. What is the mass of a single atom of carbon?

mixer [17]

Amount of substance can be measured in the number of moles.
Avagadros constant states that 1 mol of any substance is made of 6.022 x 10^23 units.
These units could be atoms making up elements or molecules making up compounds
1 mol of C is made of 6.022 x 10^23 atoms of C
Since 1 mol of C has a mass of 12.011 g
Therefore 6.022 x 10^23 atoms of C weigh 12.011 g
Then 1 atom of C weighs -12.011 g / 6.022 x 10^23 atoms = 1.99 x 10^(-23) g
Mass of 1 C atom is 1.99 x 10^(-23) g

8 0

3 years ago