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Olenka [21]
3 years ago
13

For the reaction Cu2S(s)⇌2Cu+(aq)+S2−(aq)Cu2S(s)⇌2Cu+(aq)+S2−(aq), the equilibrium concentrations are as follows: [Cu+]=1.0×10−5

[Cu+]=1.0×10−5 M, [S2−]=1.0×10−2[S2−]=1.0×10−2 M. The equilibrium constant is:
Chemistry
1 answer:
klio [65]3 years ago
8 0

Answer:

1x10⁻¹²

Explanation:

  • Cu₂S(s) ⇌ 2Cu⁺(aq) + S²⁻(aq)

At equilibrium:

  • [Cu⁺] = 1.0x10⁻⁵ M
  • [S²⁻] = 1.0x10⁻² M

The equilibrium constant for the the reaction can be written as:

  • Keq = [Cu⁺]² * [S²⁻]

[Cu⁺] is squared because it has a stoichiometric coefficient of 2 in the reaction. <em>Cu₂S has no effect on the constant because it is a solid</em>.

Now we can <u>calculate the equilibrium constant</u>:

  • Keq = (1.0x10⁻⁵)² * 1.0x10⁻² = 1x10⁻¹²
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