Question

The 15-Mg tank car A and 25-Mg freight car B travel towards each other with the velocities shown. If the coefficient of restitution between the bumpers is e = 0.8, determine the speed of each car just after the collision. Part A. Determine the speed of the car A just after the collision. Part B. Determine the speed of the car B just after the collision.

Answer 1

The speed of the car A is 6.05 m/s and  the speed of the car B just after the collision 7.65 m/s.

Ma=15 mg , Mb=25mg

Vai=5 m/s   vbi=7 m/s

We know coeffecient of restitution

e=|Vaf-Vbf/Vai-Cbi|

0.8=|Vaf-Vbf/5-7|

Vaf-Vbf=1.6

MaVa+mbVb=MaVaf+MbVbf

15*5*25*7=15Vaf+25Vbf

3Vaf+5Vbf=50

sovleving eq 1 and 2

Vbf =6.05 m/s

Vaf=7.65 m/s

The speed of a change in an object's location in any direction. The distance traveled divided by the time required to travel that distance is the definition of speed.Due to its lack of magnitude and merely having a direction, speed is a scalar number. The average speed of an object can be determined if you know the distance traveled and the time it took. Distance times speed is how speed is calculated.

Learn more about speed here:

brainly.com/question/28224010

#SPJ4