The 15-Mg tank car A and 25-Mg freight car B travel towards each other with the velocities shown. If the coefficient of restitut
1 answer:
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Answer:
R = 0.5825 k ohm
Explanation:
given data
vD = 0.75 V
iD = 1mA
resistor R = 15-V
solution
we get here first vD that is
vD =
vD = 0.825
so
iD = Ise ×
n = 1
so we can say
so it will
iD2 = iD1 ×
put here value and we get
iD2 = 1 ×
iD2 = 1 ×
iD2 = 20.086 mA
so
R will be
R =
R = 0.5825 k ohm
Answer:
the velocity of the cylinder after dropping an additional 1.28 m is 1.15 m/s
Explanation:
Using the work energy system
The initial kinetic energy is ;
where;
= mass of the cylinder = 7.7 kg
initial velocity of the cylinder = 0.49 m/s
= moment of inertia of the drum about O
mass of the drum = 10.5 kg
radius of gyration = 0.3 m
= angular velocity of the drum
The final kinetic energy is also calculated as:
Similarly, The workdone by all the forces on the cylinder can be expressed as:
where;
g = acceleration due to gravity
h = drop in height of the cylinder
M = frictional moment at O
Finally, using the work energy application;
2.426 + 11.04 = 10.10
13.466 = 10.10
=
= 1.333
Thus, the velocity of the cylinder after dropping an additional 1.28 m is 1.15 m/s