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adell [148]
3 years ago
11

What is the name of CaCl2 7H2o

Chemistry
1 answer:
Tanya [424]3 years ago
6 0

Answer:

calcium chloride dihydrate

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Which statement is true regarding a hydrogen bond? It is weaker than dipole interaction forces. It is weaker than London dispers
Rom4ik [11]
I believe the answer is C: "<span>It occurs when a hydrogen atom bonds with electropositive atoms."</span>
4 0
3 years ago
Read 2 more answers
Now let us refine our model by noting that there is a second source of Na+ ions in the cell: NaI. Suppose the outside of the cel
MArishka [77]

Answer:

E=55mV

Explanation:

Hello,

Considering the given information, the new concentration of Na+inside will be (13.6 + 4) mM = 17.6 mM, and outside will be (150 + 0.04) mM = 150.04 mM due to the previous specified conditions.

Now, the recalculation of the Nerst potential at the supposed temperature of 25 °C (which is modifiable) is done via:

E=\frac{RT}{zF} ln(\frac{C_{Na^+,outside}}{C_{Na^+,outside}} )\\\\E=\frac{8.314\frac{J}{mol*K}*298K}{1*9.65x10^4\frac{C}{mol} } *ln(\frac{150.04}{17.6} )=0.055V*\frac{1x10^3mV}{1V} \\E=55mV

Best regards.

8 0
3 years ago
Consider the following four pairs of molecules. You may use 1H-NMR, 13C-NMR, or IRspectroscopyto differentiate the structures, b
GREYUIT [131]

Answer:

The question is incomplete. The structures were not added to the question. Find attached of the structure and the given answer.

Explanation:

See the attached file for explanation

4 0
3 years ago
A sample of water is cooled from 45°C to 25°C
juin [17]

Answer:

1000 g

Explanation:

Given data:

Initial temperature of water = 45°C

Final temperature of water = 25°C

Heat released = 20 cal (4184×20 = 83680 j)

Mass of water = ?

Solution:

Specific heat capacity:

It is the amount of heat required to raise the temperature of one gram of substance by one degree.

Specific heat capacity of water is 4.184 j/g.°C

Formula:

Q = m.c. ΔT

Q = amount of heat absorbed or released

m = mass of given substance

c = specific heat capacity of substance

ΔT = change in temperature

ΔT = 25°C - 45°C

ΔT = -20°C

83680 j = m × 4.184 j/g.°C ×20°C

83680 j = m × 83.68 j/g

m = 83680 j / 83.68 j/g

m = 1000 g

5 0
3 years ago
What is the location, mass size, and charge of the 3 subatomic particles?
lidiya [134]
The neutron and proton are both located in the nucleus of the atom whereas the electron is orbiting the nucleus. The average mass of the proton is 1.6726219 × 10-27 kilograms and the neutron is practically the same. The electron’s mass is 9.10938356 × 10-31 kilograms. The charge of the proton is +1e or 1.602x10-19 C and the neutron is neutral. The charge of an electron is 1.60217662 × 10-19 coulombs
6 0
3 years ago
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