What maximum fraction of the air in the room could be displaced by the gaseous nitrogen?

1 answer:

6 0

The atmosphere is made up of different gases. The air in any room can be likened to the air outside and so the same proportions of gases would apply. The air surrounding the earth is composed of 78% nitrogen, 21% oxygen, 1% argon and trace amounts of other gases including carbon dioxide. These values indicate therefore that the maximum fraction to be displaced is 78%.

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The balanced chemical equation for the reaction of copper (Cu) and silver nitrate (AgNO3) is shown below.

lesantik [10]

Remark
The balance numbers in front of Ag and AgNO3 are both 2. That number is in moles.

Rule: if the moles are the same in the equation, then whatever you are given for one, will be the same for the other. So you have 0.854 moles of Ag. You will also have 0.854 moles of AgNO3

Answer: 0.854 <<<<<

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3 years ago

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Defintion of isometry

BARSIC [14]

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3 years ago

Where would you have the least mass?

beks73 [17]

Answer:

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Explanation:

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3 years ago

What is the mole fraction, X, of solute and the molality, m (or b), for an aqueous solution that is 15.0% NaOH by mass?

GalinKa [24]

Hello!

a) The mole fraction of solute of a 15% NaOH aqueous solution can be calculated in the following way:

First, we have to assume that we have 100 grams of solution. This will simplify the calculations.

Now, we know that this solution has 15 grams of NaOH and 85 grams of water. We can calculate the number of moles of each one in the following way:

$molesNaOH= 15 g NaOH*\frac{1molNaOH}{39,997 g NaOH}=0,3750 moles NaOH \\ \\ moles H_2O=85 gH_2O* \frac{1 mol H_2O}{18 g H_2O}=4,7222 moles H_2O$

To finish, we calculate the mole fraction by dividing the moles of NaOH between the total moles:

$X_{NaOH}= \frac{moles NaOH}{total moles}= \frac{0,3750 moles NaOH}{0,3750 moles NaOH+4,7222 molesH_2O} =0,073$

So, the mole fraction of NaOH is 0,073

b) The molality (moles NaOH/ kg of solvent) of a 15% NaOH aqueous solution can be calculated in the following way:

First, we have to assume that we have 100 grams of solution. This will simplify the calculations.

Now, we know that this solution has 15 grams of NaOH and 85 grams (0,085 kg) of water. We can calculate the moles of NaOH in the following way:

$molesNaOH= 15 g NaOH*\frac{1molNaOH}{39,997 g NaOH}=0,3750 moles NaOH$

Now, we apply the definition of molality to calculate the molality of the solution:

$mNaOH= \frac{moles NaOH}{kg_{solvent}}= \frac{0,3750 moles NaOH}{0,085 kg H_2O}=4,41 m$

So, the molality of this solution is 4,41 m

Have a nice day!

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3 years ago

4) In the experiment, why do you think they started with water that was the same temp (118 °F) for each

kondor19780726 [428]

Answer:

4. I think that they started with water that was the same tsmpurature because if they didnt start with the same temp of water then it would be harder to tell which one was better. and could hold the most heat.

5. yes i think it would matter, because if you have more water in one cup it might stay warmer than it would with the cups with less water, and if it was thicker it would hold mor heat because it is not so thin that the heat is just gonna come out it has to come through more for the heat to get out.

Explanation:

sorry if these are to long but thats how i would answer them.

hope it helped

3 0

2 years ago