Answer:
So the car was speeding more moving towards North
Explanation:
As we know that during the collision of two cars total momentum before collision and after collision must be conserved
So here we can say that after collision two cars are locked and moved together Exactly towards North-East
So here momentum of two cars must be exactly same before collision in East and North directions
So we will have
So the car was speeding more moving towards North
26
atomic number is number of protons.
ion has + charge. lost electrons.
Answer:
250 mL
Explanation:
If the density is more than that of water (in this case it is) it will sink to the bottom of the container holding water (if it fits).
That being the case, the amount of water displaced = the volume of the castle.
Answer: 250 mL
Answer:
120 km/hr
Explanation:
Let D be the distance between the rocket and the camera as the rocket is moving upwards. Let d be the distance the rocket moves and L be the distance between the camera and the base of the rocket = 4 km.
Now, at any instant, D² = d² + L²
= d² + 4²
= d² + 16 since the three distances form a right-angled triangle with the distance between the rocket and the camera as the rocket is moving upwards as the hypotenuse side.
differentiating the expression to find the rate of change of D with respect to time, dD/dt ,we have
d(D²)/dt = d(d² + 16)/dt
2DdD/dt = 2d[d(d)/dt]
dD/dt = 2d[d(d)/dt] ÷ 2D
Now d(d)/dt = vertical speed of rocket = 200 km/hr
dD/dt = 200d/D [D = √(d² + 16)]
dD/dt = 200d/[√d² + 16]
Now substituting d = 3 km, the distance the rocket has risen into the equation, we have
dD/dt = 200(3)/[√(3² + 16)]
dD/dt = 600/[√(9 + 16)]
dD/dt = 600/√25
dD/dt = 600/5
dD/dt = 120 km/hr
So, the speed at which the distance from the camera to the rocket changing when the rocket has risen 3 km is 120 km/hr.
Removing an electron from a neutral atom will result in an atom that is positive.