Answer:
Explanation:
A )
v² = u² + 2 a s
u = 0
s = 2.5
a = 9.8
v² = 2 x 9.8 x 2.5 = 49
v = 7 m /s
B )
time required to fall by first 2.5 m , t₁
s = 1/2 a t₁²
2.5 = .5 x 9.8 t₁²
t₁ = .714 s
time required to fall by 10 m
s = 1/2 a t₂²
10 = .5 x 9.8 t₂²
t₂ = 1.43 s
time required to fall by last 7.5 m
= t₂ - t₁
= 1.43 - .714
= .72 s
C )
time taken by second = .72 s
For second let initial velocity required be u
s = ut + 1/2 g t²
10 = u x .72 + .5 x 9.8 x .72²
10 = u x .72 + 2.54
u = 10.36 m /s
Answer:
Relative to Carlos the Whataburger is moving at 0 speed.
Explanation:
Carlos speed, = 35 m/s
speed of another car, = -25 m/s
The speed of the Whataburger, = 35 m/s since it is in the same car as Carlos.
The relative of the Whataburger to Carlos is given as;
Therefore, Relative to Carlos the Whataburger is moving at 0 speed.
Answer:
In the picture.
Explanation:
I hope that it's a clear solution and explanation.