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3 years ago

If the absolute pressure of a gas is 550.280 kPa, its gage pressure is

Physics

2 answers:

Ray Of Light [21]3 years ago

8 0

Answer:

The Gage pressure is 448.955 kPa.

(b) is correct option.

Explanation:

Given that,

Absolute pressure = 550.280 Pa

Gage pressure :

The Gage pressure is equal to the subtract the absolute pressure from atmospheric pressure.

We need to calculate the Gage pressure

Using formula of Gage pressure

$P_{ab}=P_{g}+P_{atm}$

$P_{g}=P_{ab}-P_{atm}$

Put the value into the formula

$P_{g}=550.280-101.325$

$P_{g}=448.955\ kPa$

Hence, The Gage pressure is 448.955 kPa.

Gwar [14]3 years ago

6 0

If the absolute pressure of a gas is 550.280 kPa, its gage pressure is <span> a. 101.325 kPa.
b. 448.955 kPa.
c. 651.605 kPa.
d. 277.280 kPa.</span>

The answer is B.

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Complete Question

A 100-W (watt) light bulb has resistance R=143Ω (ohms) when attached to household current, where voltage varies as V=V0sin(2πft), where V0=110 V, f=60 Hz. The power supplied to the bulb is P=V2R J/s (joules per second) and the total energy expended over a time period [0,T] (in seconds) is $U = \int\limits^T_0 {P(t)} \, dt$

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Explanation:

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=> $U = \frac{110^2}{144} [\frac{t}{2} - [\frac{1}{2} * \frac{sin(240 \pi t)}{240 \pi} ] ]\left | 18000} \atop {0}} \right.$

$U = \frac{110^2}{144} [\frac{18000}{2} - [\frac{1}{2} * \frac{sin(240 \pi (18000))}{240 \pi} ] ]$

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