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3 years ago

Which substance is a diatomic molecule

Chemistry

2 answers:

aleksandrvk [35]3 years ago

8 0

heteronuclear diatomic molecule: .....hydrogen,chlorine,bromine,nitrogen etc

Neporo4naja [7]3 years ago

4 0

There are a lot of substances. The substances are hydrogen, nitrogen, oxygen, fluorine, chlorine, bromine, and iodine. Diatomic Molecule consists of atoms from only two different elements.

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BRAINLIESTTT ASAP!! PLEASE HELP ME :)

deff fn [24]

Answer:

True

Explanation:

There are two types of Van der waals forces which are intermolecular bonds. These bonds are London dispersion forces and Dipole-dipole attractions.

The london dispersion forces are weak attractions found between non-polar molecues and noble gas.

The attractions here is as a result of the fact that non-polar molecules or atoms sometimes becomes polar because the constant motion of its electrons may lead to an uneven charge distribution at an instant. This leads to the formation of a temporary dipole or instantaneous dipole. The dipole can induce the neighbouring molecules to be distorted and they form dipoles as well.

7 0

4 years ago

Read 2 more answers

The digestive tract converts food into materials and energy. True False

dolphi86 [110]

Answer:

true

Explanation:

The digestive tract is made up of organs that food and liquids travel through when they are swallowed, digested, absorbed, and leave the body as feces. These include the mouth, pharynx (throat), esophagus, stomach, small intestine, large intestine, rectum, and anus.

4 0

4 years ago

If the total pressure of water vapor and hydrogen gas is 1.02 atm and the partial pressure of the water at 22.0 C is 0.13 atm, w

ira [324]

Answer:

0.89 atm is the pressure of the hydrogen gas

Explanation:

We can use the molar fractions to solve this

Sum of molar fractions (hydrogen + water vapor) = 1

Molar fraction = Pressure gas / Total pressure

Molar fraction water vapor = 0.13 atm/1.02 atm = 0.127

1 - 0.127 = 0.873 (Molar fraction H2)

0.873 = Pressure H2 / Total pressure

0.873 = Pressure H2 / 1.02 atm

0.873 . 1.02atm = 0.89 atm

8 0

4 years ago

What is the name for this molecule? a skeletal model of an 8-carbon zig zag chain. there is a double bond between the first and

yKpoI14uk [10]

The name of the compound by using the IUPAC nomenclature of organic compounds is 1 -octene. The correct option is the last option - 1-octene.

<h3>Nomenclature of Organic compounds</h3>

From the question, we are to determine the name of the given molecule.

To name the compound, we will follow the IUPAC rules.

Some of IUPAC rules are

Find the longest continuous carbon chain. Determine the root name for this parent chain.
For Alkenes (organic compounds with double bond), number the chain of carbons that includes the C=C so that the C=C has the lower position number. Change “ane” to “ene” and assign a position number to the first carbon of the C=C.

The given compound has 8 carbons and a double bond. The root name of the compound is octane.

By IUPAC rules, the compound is an Octene.

Since the double bond is between carbon-1 and carbon-2. The compound becomes 1-octene.

Hence, the name of the compound by using the IUPAC nomenclature of organic compounds is 1 -octene. The correct option is the last option - 1-octene.

Learn more on Nomenclature of Organic compounds here: brainly.com/question/26754333

The diagram for the compound is attached below.

8 0

3 years ago

If a gas occupies 1532.7 mL at standard temperature, what volume does it occupy at 49.4 ºC if the pressure remains constant?

ElenaW [278]

Answer:

a. 1810mL

Explanation:

When conditions for a gas change under constant pressure (and the number of molecules doesn't change), it follows Charles' Law:

$\dfrac{V_1}{T_1}=\dfrac{V_2}{T_2}$ where the temperatures must be measured in Kelvin

To convert from Celsius to Kelvin, add 273, or use the equation: $T_C+273=T_K$

For this problem, one must also recall that standard temperature is 0°C (or 273K).

So, $T_1 = 273[K]$ , and $T_2 = (49.4+273)[K]=322.4[K]$ .

$\dfrac{V_1}{T_1}=\dfrac{V_2}{T_2}$

$\dfrac{(1532.7[mL])}{(273[K])}=\dfrac{V_2}{(322.4[K])}$

$\dfrac{(1532.7[mL])}{(273[K\!\!\!\!\!{-}])}(322.4[K\!\!\!\!\!{-}] )=\dfrac{V_2}{(322.4[K]\!\!\!\!\!\!\!\!\!\!\!\!\!\!\!\!\!\!\!\!\!\!\!{----})}(322.4[K]\!\!\!\!\!\!\!\!\!\!\!\!\!\!\!\!\!\!\!\!\!\!\!{----})$

$1810.04571428[mL]=V_2$

Adjusting for significant figures, this gives $V_2=1810[mL]$

4 0

2 years ago