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3 years ago

Convection currents not only in the Earth's core but in what?

Physics

1 answer:

Verdich [7]3 years ago

3 0

Answer:

B. When a dense substance is warmer than a less dense substance

Explanation:

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A positive charge of 0.00047 C is 15 m from a negative charge of 0.00089 C. What is the force of one of the charges due to the o

Lady_Fox [76]

Answer:

16.732 N

Explanation:

Given:

q1 = 0.00047 C = 4.7 x 10^-4 C

q2 = 0.00089 C = 8.9 x 10^-4 C

d = 15 m

k = 9 x 10^9 N m^2 / C^2

To Find:

F = ?

Solution:

F = k x q1 x q2/d^2

F = 9 x 10^9 x 4.7 x 10^-4 x 8.9 x 10^-4 / 15 x 15

F = 9 x 4.7 x 8.9 x 10^9 x 10^-4 x 10^-4 / 225

F = 9 x 4.7 x 8.9 x 10^9 x 10^-8 / 225

F = 9 x 4.7 x 8.9 x 10 / 225

F = 418.3/25

F = 1673.2/100

Therefore, F = 16.732 N

PLZ MARK ME AS BRAINLIEST!!!

8 0

3 years ago

A rock that has magnetic properties is

Dahasolnce [82]

Answer: lodestone

Explanation:

ITS LODESTONE

6 0

2 years ago

What is brownion motion

Alex777 [14]

Answer: Brownion motion is the erratic random movement of microscopic particles in a fluid, as a result of continuous bombardment from molecules of the surrounding medium.

Explanation:

Brownian motion is the random movement of particles in a fluid due to their collisions with other atoms or molecules.

4 0

3 years ago

A bug on the surface of a pond is observed to move up and down a total vertical distance of 6.5 cm , from the lowest to the high

m_a_m_a [10]

Answer:

factor that bug maximum KE change is 0.52284

Explanation:

given data

vertical distance = 6.5 cm

ripples decrease to = 4.7 cm

solution

We apply here formula for the KE of particle that executes the simple harmonic motion that is express as

KE = (0.5) × m × A² × ω² .................1

and kinetic energy is directly proportional to square of the amplitude.

$\frac{KE2}{KE1} = \frac{A2^2}{A1^2}$ .............2

$\frac{KE2}{KE1} = \frac{4.7^2}{6.5^2}$

$\frac{KE2}{KE1}$ = 0.52284

so factor that bug maximum KE change is 0.52284

5 0

3 years ago

An ideal spring hangs from the ceiling. A 2.15 kg mass is hung from the spring, stretching the spring a distance d = 0.0895 m fr

Igoryamba

Answer:

The kinetic energy of the mass at the instant it passes back through the equilibrium position is 0.06500 J.

Explanation:

Given that,

Mass = 2.15 kg

Distance = 0.0895 m

Amplitude = 0.0235 m

We need to calculate the spring constant

Using newton's second law

$F= mg$

Where, f = restoring force

$kx=mg$

$k=\dfrac{mg}{x}$

Put the value into the formula

$k=\dfrac{2.15\times9.8}{0.0895}$

$k=235.41\ N/m$

We need to calculate the kinetic energy of the mass

Using formula of kinetic energy

$K.E=\dfrac{1}{2}mv^2$

Here, $v = A\omega$

$K.E=\dfrac{1}{2}m\times(A\omega)^2$

Here, $\omega=\sqrt{\dfrac{k}{m}}^2$

$K.E=\dfrac{1}{2}m\times A^2\sqrt{\dfrac{k}{m}}^2$

$K.E=\dfrac{1}{2}kA^2$

Put the value into the formula

$K.E=\dfrac{1}{2}\times235.41\times(0.0235)^2$

$K.E=0.06500\ J$

Hence, The kinetic energy of the mass at the instant it passes back through the equilibrium position is 0.06500 J.

8 0

3 years ago