Answer:
a)Q=71.4 μ C
b)ΔV' = 10.2 V
Explanation:
Given that
C ₁= 8.7 μF
C₂ = 8.2 μF
C₃ = 4.1 μF
The potential difference of the battery, ΔV= 34 V
When connected in series
1/C = 1/C ₁ + 1/C₂ + 1/C₃
1/ C= 1/8.4 +1 / 8.4 + 1/4.2
C=2.1 μF
As we know that when capacitor are connected in series then they have same charge,Q
Q= C ΔV
Q= 2.1 x 34 μ C
Q=71.4 μ C
b)
As we know that when capacitor are connected in parallel then they have same voltage difference.
Q'= C' ΔV'
C'= C ₁+C₂+C₃ (For parallel connection)
C'= 8.4 + 8.4 + 4.2 μF
C'=21 μF
Q'= C' ΔV'
Q'=3 Q
3 x 71.4= 21 ΔV'
ΔV' = 10.2 V
There’s a first
“clump”/drum beat every half second. That clump will travel about 170m in half
a second. Someone 170m away would do their “clump” as the second “clump” was
taking place. I think. <span>
</span>
C-Non-metals. There are tons of them.
Answer:
distance= 10 km
displacement= 7.21 km
Explanation:
distance= scalar (only magnitude)
displacement= vector (magnitude & direction)
distance= 6 km+ 4 km
= 10 km
displacement= shortest difference btwn 2 pts=
sqrt( 6^2+4^2)
sqrt(52)
7.21 km
