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vodomira [7]
3 years ago
5

Valleys have dense population but plateaus don't have dense population.why?

Physics
1 answer:
Juliette [100K]3 years ago
6 0

Answer:

Another very important reason why people prefer to live in valleys instead of plateaus is because of available sources of water. This conducive nature of valleys in turn accommodate factors like economic growth,social and cultural, which in turn attract more people, hence making these areas densely populated.

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High-energy particles are observed in laboratories by photographing the tracks they leave in certain detectors; the length of th
murzikaleks [220]

Answer:

Lifetime = 4.928 x 10^-32 s  

Explanation:

(1 / v2 – 1 / c2) x2 = T2

T2 = (1/ 297900000 – 1 / 90000000000000000) 0.0000013225

T2 = (3.357 x 10^-9 x 1.11 x 10^-17) 1.3225 x 10^-6

T2 = (3.726 x 10^-26) 1.3225 x 10^-6 = 4.928 x 10^-32 s  

4 0
3 years ago
2. Sara y Antonio son mellizos. Cuando nacieron, Sara pesaba 600 gramos más que Antonio. Sus pesos ya se han igualado, gracias a
valkas [14]

Answer:

8,25 creo

Explanation:

nose no estoy segura

7 0
3 years ago
A monk is sitting atop a mountain in complete rest in meditation. What is the kinetic Energy of the monk? (assume mass of 65 kg
Genrish500 [490]

Answer:

no kinetic energy

hope this helps! :-D

Explanation:

the monk is not moving

7 0
3 years ago
Thermal conductivity of a material is given as 129Btuft–¹ h–¹°F–¹.Calculate this thermal conductivity in Jm–¹s–¹°C–¹(Given: 1Btu
ss7ja [257]

Answer:

223.25 $\text{Jm}^{-1}\text{s}^{-1}^\circ\text{C}^{-1}$

Explanation:

The thermal conductivity of an object is defined as the measure or the ability of the object to transfer heat or conduct heat through its body.

In the context, the thermal conductivity of the material is given as

$=129 \text{ Btu ft}^{-1}\text{h}^{-1}^\circ\text{F}^{-1}$

And it is given that :

1 Btu = 1055 J

1 ft = 0.3048 m

$1^\circ F = \frac{5}{9}^\circ C$

We know that 1 h = 3600 s

So the thermal conductivity of the material in $\text{Jm}^{-1}\text{s}^{-1}^\circ\text{C}^{-1}$ is  :

Thermal conductivity :

$=\frac{129 \text{ Btu}}{1 \text{ ft }\times \text{1 h}\times 1^\circ\text{F}}$

$=\frac{129 \times 1055 \text{ J}}{0.3048 \text{ m} \ \times 3600 \text{ s}\ \times \frac{5}{9}^\circ \text{C}}$

=  223.25 $\text{Jm}^{-1}\text{s}^{-1}^\circ\text{C}^{-1}$

3 0
3 years ago
Light enter the container of the liquid at the angle 37° to the normal refraction beam makes an angle of 27° with the normal. Ca
Sliva [168]

Answer: 1.33

Explanation:

We would apply Snell's law which is expressed as

niSinθi = nrSinθr

where

θi = angle of incidence

θr = angle of refraction

ni = index of refraction of the incident medium(air)

nr = index of refraction of the refractive medium(liquid in this case)

From the information given,

ni = 1(index for air)

θi = 37

θr = 27

By substituting these values into the formula, we have

1 * sin37 = nr * sin27

nr = sin37/sin27

nr = 1.33

The index of the liquid is 1.33

6 0
1 year ago
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