Answer:
0.285
Explanation:
Given two forces of different magnitude, it is important to note that the product of normal force and coefficient of kinetic friction should be equal to the sum of these two forces at equilibrium. Therefore, this can be Mathematically expressed as:
where N is normal force,
is coefficient of static friction, F is force and subscripts 1 and 2 represent larger and smaller magnitude forces respectively. Making the subject of the formula then
Since normal force N is also given by mg where m is mass of object and g is acceleration due to gravity then substituting N with mg we obtain that
and substituting the figures given in the question, taking g as 9.81 we obtain that
Hence,the coefficient of kinetic energy is 0.285 as calculated
Falseeeeeeeeeeeeeeeeeeeeeeeeeeeee
Explanation:
Exothermic
Because here Energy is released.
Macromolecule polymers are assembled by the connecting of monomers. An -OH group is detached from one monomer and a hydrogen atom is detached from an additional in a procedure named dehydration synthesis in the monomers bond. For every subunit supplementary to a macromolecule in which one water molecule is detached. Macromolecule polymers are broken down by breaking bonds among subunits. This procedure is named hydrolysis and is the opposite of dehydration. During hydrolysis the hydrogen atom is supplementary to one monomer and a hydroxyl cluster to the other and by breaking the covalent bond in the middle of the monomers.
The easiest way to answer this question is by realizing there are relating the velocities of the two cars. To tackle this problem, you have to understand the picture. Car 1 travels at 35m/s and Car 2 travels at 25m/s. Based on relative velocities, we can understand that Car 1 travels 10m/s faster than Car 2 every second. So we can interpret Car 1's relative velocity to Car 2 as 10m/s. Car 1 needs to travel 10m/s till a point of catching up to Car 2 which is 462m away.
v = 10m/s
d = 462m
v = d/t
(10) = (462)/t
t = 46.2s
So it takes 46.2 seconds for Car 1 to catch up to Car 2, but the question is asking how far does Car 1 travel to catch up. So we have to use Car 1's velocity and not the relative velocity:
v = 35m/s
v = d/t
(35) = d/(46.2)
d = 1617m
Car 1 traveled a total distance of 1617m.
