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Andreyy89
2 years ago
5

A person in a factory has to lift a box on to a shelf.

Physics
1 answer:
vodomira [7]2 years ago
6 0

Answer:

A

Explanation:

A is the right answer abi

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What is required for both the light-dependent and light-independent reactions to proceed?
djyliett [7]
<span>ATP is required for both light-dependent and light-independent reactions.
ATP stands for </span> adenosine triphosphate.
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2 years ago
A positively charged atom has
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It has a positive charge
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3 years ago
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A young woman walks up 55 steps to the top of a water slide. She slides
navik [9.2K]

Answer:

potential energy PE = M g h

KE at bottom = 1/2 M V^2

Regardless of the slope of the slide the change in energy is the same

1/2 V^2 = g h

V = (2 g h)^1/2 = (2 * 9.8 m/s^2 * 10 m)^1/2 = 14 m / s

Perhaps the question says that h = 55 * .1 = 5.5 m

Then V = (2 * 9.8 * 5.5) = 10.4 m/s

5 0
2 years ago
An astronaut has a mass of 100 kg and has a weight and if 370 N on Mars. What is the gravitational strength on Mars?
Reika [66]

Answer:

3.7 N/kg

Explanation:

The gravitational strength refers to the amount of gravity acting per unit mass. Hence in this case,

Gravitational Strength = Weight / Mass

= 370 / 100

= <u>3</u><u>.</u><u>7</u><u>N</u><u>/</u><u>k</u><u>g</u>

4 0
3 years ago
A body of mass 100g moving with a velocity of 10.0m/s collides with a wall .if after the collision it moves with a velocity of 2
ch4aika [34]

Answer:

-1.2 kg - m/s

Explanation:

\pink{\frak{Given}}\begin{cases}\textsf{ A body of mass 100g moving with a velocity of 10.0m/s collides with a wall .}\\\textsf{ After the collision it moves with a velocity of 2.0m/s in the opposite direction.}\end{cases}

And we need to find out the change in momentum of the body . Here ,

  • velocity before collision (u) = 10m/s
  • velocity after collision (v) = 2m/s .

We know that momentum is defined as amount of motion contained in a body . Mathematically ,

\sf\longrightarrow momentum (p)= mass(m) * velocity(v)

Therefore change in momentum will be,

\sf\longrightarrow \triangle p = mv - mu

Since the direction of velocity changes after the collision , the velocity will be -2m/s .

\sf\longrightarrow \Delta p = 100g( -2m/s -10m/s) \\

\sf\longrightarrow \Delta p =\dfrac{100}{1000}kg ( -12m/s)  \\

\sf\longrightarrow \Delta p   = 0.1 kg * -12m/s \\

\sf\longrightarrow \boxed{\bf \Delta p = -1.2 \ kg-m/s} \\

7 0
2 years ago
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