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Furkat [3]
3 years ago
9

a capacitor of unknown charged capacitance c is charged to 100v and the connected across an intially uncharged 60micro f capacit

or .if the final potenial diffrence across the 60micro-f capacitor is 40v ,determine c
Physics
1 answer:
poizon [28]3 years ago
6 0

Answer:

hi thank you for your free point

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plates of a parallel-plate capacitor are 2.50 mm apart, and each carries a charge of magnitude 85.0 nC . The plates are in vacuu
tensa zangetsu [6.8K]

Answer:

12500 V

Explanation:

The electric field in the gap of a parallel-plate capacitor is uniform, so the following relationship between electric field strength, potential difference and distance can be used:

\Delta V = E d

where

\Delta V is the potential difference between the plates

E is the electric field strength

d is the distance between the plates

For the capacitor in this problem, we have

E=5.00\cdot 10^6 V/m

d = 2.50 mm = 2.50\cdot 10^{-3} m

Substituting, we find

\Delta V = (5.00\cdot 10^6)(2.50\cdot 10^{-3})=12500 V

3 0
3 years ago
Two people stand facing each other at roller skating rink then push off each other
9966 [12]

a) 0 kg m/s

b) 0 kg m/s

c) +3 m/s

d) 60 N

Explanation:

a)

The momentum of an object is a vector quantity given by:

p=mv

where

m is the mass of the object

v is the velocity of the object

In this problem, we have a system of two people, so the total momentum will be the sum of the individual momenta of the two people:

p=p_1 + p_2

Which can be rewritten as

p=m_1 u_1 + m_2 u_2

where m_1,m_2 are the masses of the two people and u_1,u_2 their initial velocities.

However, the two people are initially at rest, so

u_1 = 0\\u_2 = 0

Therefore the total momentum is

p=0+0=0

b)

The principle of conservation of momentum states that when there are no external forces acting on a system, the total momentum of the system is conserved, so we can write:

p_i = p_f

where

p_i is the total momentum of the system before

p_f is the total momentum of the system after

In this problem,

p_i = 0

As we calculated in part a: this is because the total momentum of the two people before they push off each other is zero.

Therefore, according to the law of conservation of momentum,

p_f = p_i = 0

So the total momentum is zero also after they push off each other.

c)

The total momentum of the girl and the boy after they push off each other can be written as:

p_f = m_1 v_1 + m_2 v_2 (1)

where:

m_1 = 30 kg is the mass of the girl

v_1 = -5 m/s is her velocity (she moves backward, so the negative sign)

m_2 = 50 kg is the mass of the boy

v_2 is the velocity of the boy

As calculated in part b), we also know that the total momentum of the girl and the boy is

p_f = 0 (2)

By combining eq(1) and eq(2) we get

0=m_1 v_1 + m_2 v_2

And solving for v2 we find the velocity of the boy:

v_2=-\frac{m_1 v_1}{m_2}=-\frac{(30)(-5)}{50}=+3 m/s

and the positive sign means he is moving forward.

d)

We can solve this part by applying the impulse theorem, which states that the change in momentum of an object is equal to the product between the force applied on it and the duration of the collision:

\Delta p = F\Delta t

where

\Delta p is the change in momentum

F is the force

\Delta t is the time during which the force is applied

In this problem:

\Delta t = 2.5 s

For the boy, the change in momentum is:

\Delta p = m_2 (v_2 - u_2)

And since

m_2 = 50 kg\\u_2 = 0 m/s\\v_2 = 3 m/s

We have

\Delta p = (50)(3-0)=150 kg m/s

So, the force exerted between the boy and the girl is:

F=\frac{\Delta p}{\Delta t}=\frac{150}{2.5}=60 N

8 0
3 years ago
A rocket is launched from the launch pad at a speed of 700 km/hr.
Juliette [100K]

Answer:

Explanation:

Vm = Δs/Δt

700km/h = Δs/1.5h

700 = Δs/1.5

\frac{700}{1} = \frac{S}{1.5}

S = 700 x 1.5

S = 1050 Km

*(S = Δs)

Answer: The rocket will have traveled 1050 Km

Hope this help ☺

5 0
3 years ago
A brave but inadequate rugby player is being pushed backward by an opposing player who is exerting a force of 780 N on him. The
stich3 [128]

Answer:

f = 556.4 N

Explanation:

Mass of the losing player with its all equipment is given as

M = 86 kg

Net force applied on him by another player is given as

F = 780 N

also we know that acceleration of the losing player is given as

a = 2.6 m/s^2

now by Newton's 2nd law we will have

F - f = ma

780 - f = 86(2.6)

780 - f = 223.6

f = 556.4 N

7 0
2 years ago
In the lab, you performed a trial where the fan was turned
beks73 [17]

Answer:

Simple Response The first part of the graph is a straight diagonal line and the second part of the graph is a straight horizontal line. The slope of the first part of the graph is positive, indicating that the cart increased in speed, and was therefore accelerating for the first four seconds. After the fourth second, the slope of the line is zero, indicating that the cart moved at a constant speed and did not accelerate any more because the fan was turned off.

Explanation:

7 0
3 years ago
Read 2 more answers
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