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saul85 [17]
3 years ago
6

What is the pressure of a sample of gas at a volume of .335 L if it occupies 1700 mL at 850 mm Hg?

Chemistry
1 answer:
dangina [55]3 years ago
7 0

Answer:

Pressure = 4313.43mmHg

Explanation:

P1 = ?

V1 = 0.335L

V2 = 1700mL =1700*10^-3L = 1.7L

P2 = 850mmhg

From Boyle's law, the volume of a fixed mass of gas is inversely proportional to its pressure provided that temperature remains constant.

P = k / v

K = pv. P1V1 = P2V2 = P3V3 =........=PnVn

P1V1 = P2V2

Solve for P1,

P1 = (P2*V2) / V1

P1 = (850 * 1.7) / 0.335

P1 = 4313.43mmHg

The pressure of the gas was 4313.43mmHg

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I answered a question correctly and someone deleted my answer without giving me any explanation. I don't know why someone would
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Find the density of an 8 gram rock if the water in a graduated cylinder rises from 25.0 mL to
Olin [163]

To measure the density of the stone placed in a graduated cylinder let us follow these steps bellow

  1. Measure the volume of water poured into a graduated cylinder
  2. Place the object in the water and remeasure the volume.
  3. The difference between the two volume measurements is the volume of the object.
  4. Divide the mass by the volume to calculate the density of the object.

<em>We know that the formula for density is given as </em>

Given data

Mass = 8gram

Initial Volume of water in cylinder = 25mL

Final Volume of water in cylinder  = 29mL

Hence the volume of the rock  = 29-25 = 4mL

Therefore the density of the rock = 8/4 = 2 g/mL

Learn more:

brainly.com/question/17336041

6 0
2 years ago
: If a 250. mL sample of the above buffer solution initially has 0.0800 mol H2C6H5O7 - and 0.0600 mol HC6H5O7 2- , what would be
Jet001 [13]

Answer: New concentration of HC_{6}H_{5}O^{2-}_{7} is 0.23 M.

Explanation:

The given data is as follows.

     Moles of HC_{6}H_{5}O^{2-}_{7} = 0.06 mol

     Moles of H_{2}C_{6}H_{5}O_{7} = 0.08 mol

Therefore, moles of OH^{-} added are as follows.

    Moles of OH^{-} = 0.125 \times \frac{25}{1000}

                          = 0.003125 mol

Now, new moles of HC_{6}H_{5}O^{2-}_{7} = 0.06 + 0.003125

                     = 0.063125

Therefore, new concentration of HC_{6}H_{5}O^{2-}_{7} will be calculated as follows.

       Concentration = \frac{0.063125}{0.275}

                               = 0.23 M

Thus, we can conclude that new concentration of HC_{6}H_{5}O^{2-}_{7} is 0.23 M.

4 0
3 years ago
If you burn 23.4 g of hydrogen and produce 209 g of water, how much oxygen reacted?
Kitty [74]
The chemical reaction is expressed as:

2H2 + O2 = 2H2O

To determine the amount of oxygen used in the reaction, we use the amount of water produced and the relation of the substances in the reaction we do as follows:

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