Answer:
do what you can do not what people tell you to do
Explanation:
Rydberg formula is given by:
![\frac{1}{\lambda } = R_{H}\times (\frac{1}{n_{1}^{2}}-\frac{1}{n_{2}^{2}} )](https://tex.z-dn.net/?f=%5Cfrac%7B1%7D%7B%5Clambda%20%7D%20%3D%20R_%7BH%7D%5Ctimes%20%28%5Cfrac%7B1%7D%7Bn_%7B1%7D%5E%7B2%7D%7D-%5Cfrac%7B1%7D%7Bn_%7B2%7D%5E%7B2%7D%7D%20%29)
where,
= Rydberg constant = ![1.0973731568508 \times 10^{7} per metre](https://tex.z-dn.net/?f=1.0973731568508%20%5Ctimes%2010%5E%7B7%7D%20per%20metre)
= wavelength
and
are the level of transitions.
Now, for
= 2 and
= 6
![\frac{1}{\lambda} = 1.0973731568508 \times 10^{7} \times (\frac{1}{2^{2}}-\frac{1}{6^{2}} )](https://tex.z-dn.net/?f=%5Cfrac%7B1%7D%7B%5Clambda%7D%20%3D%201.0973731568508%20%5Ctimes%2010%5E%7B7%7D%20%5Ctimes%20%28%5Cfrac%7B1%7D%7B2%5E%7B2%7D%7D-%5Cfrac%7B1%7D%7B6%5E%7B2%7D%7D%20%29)
= ![1.0973731568508 \times 10^{7} \times (\frac{1}{4}-\frac{1}{36} )](https://tex.z-dn.net/?f=1.0973731568508%20%5Ctimes%2010%5E%7B7%7D%20%5Ctimes%20%28%5Cfrac%7B1%7D%7B4%7D-%5Cfrac%7B1%7D%7B36%7D%20%29)
= ![1.0973731568508 \times 10^{7} \times (0.25-0.0278 )](https://tex.z-dn.net/?f=1.0973731568508%20%5Ctimes%2010%5E%7B7%7D%20%5Ctimes%20%280.25-0.0278%20%29)
= ![1.0973731568508 \times 10^{7} \times 0.23](https://tex.z-dn.net/?f=1.0973731568508%20%5Ctimes%2010%5E%7B7%7D%20%5Ctimes%200.23)
= ![0.2523958\times 10^{7}](https://tex.z-dn.net/?f=0.2523958%5Ctimes%2010%5E%7B7%7D%20)
![\lambda = \frac{1}{0.2523958\times 10^{7}}](https://tex.z-dn.net/?f=%5Clambda%20%3D%20%5Cfrac%7B1%7D%7B0.2523958%5Ctimes%2010%5E%7B7%7D%7D)
= ![3.9620\times 10^{-7} m](https://tex.z-dn.net/?f=3.9620%5Ctimes%2010%5E%7B-7%7D%20m%20)
= ![396.20\times 10^{-9} m](https://tex.z-dn.net/?f=396.20%5Ctimes%2010%5E%7B-9%7D%20m%20)
= ![396.20 nm](https://tex.z-dn.net/?f=396.20%20nm%20)
Now, for
= 2 and
= 5
![\frac{1}{\lambda} = 1.0973731568508 \times 10^{7} \times (\frac{1}{2^{2}}-\frac{1}{5^{2}} )](https://tex.z-dn.net/?f=%5Cfrac%7B1%7D%7B%5Clambda%7D%20%3D%201.0973731568508%20%5Ctimes%20%2010%5E%7B7%7D%20%5Ctimes%20%28%5Cfrac%7B1%7D%7B2%5E%7B2%7D%7D-%5Cfrac%7B1%7D%7B5%5E%7B2%7D%7D%20%29)
= ![1.0973731568508 \times 10^{7} \times (0.25-0.04 )](https://tex.z-dn.net/?f=1.0973731568508%20%5Ctimes%2010%5E%7B7%7D%20%5Ctimes%20%280.25-0.04%20%29)
= ![1.0973731568508 \times 10^{7} \times (0.21 )](https://tex.z-dn.net/?f=1.0973731568508%20%5Ctimes%2010%5E%7B7%7D%20%5Ctimes%20%280.21%20%29)
= ![0.230 \times 10^{7}](https://tex.z-dn.net/?f=0.230%20%5Ctimes%20%2010%5E%7B7%7D)
![\lambda= \frac{1}{0.230 \times 10^{7}}](https://tex.z-dn.net/?f=%5Clambda%3D%20%5Cfrac%7B1%7D%7B0.230%20%5Ctimes%2010%5E%7B7%7D%7D)
= ![4.3478 \times 10^{-7} m](https://tex.z-dn.net/?f=%204.3478%20%5Ctimes%2010%5E%7B-7%7D%20m%20)
= ![434.78\times 10^{-9} m](https://tex.z-dn.net/?f=434.78%5Ctimes%2010%5E%7B-9%7D%20m%20)
= ![434.78 nm](https://tex.z-dn.net/?f=434.78%20nm%20)
Now, for
= 2 and
= 4
![\frac{1}{\lambda} = 1.0973731568508 \times 10^{7} \times (\frac{1}{2^{2}}-\frac{1}{4^{2}} )](https://tex.z-dn.net/?f=%5Cfrac%7B1%7D%7B%5Clambda%7D%20%3D%201.0973731568508%20%5Ctimes%20%2010%5E%7B7%7D%20%5Ctimes%20%28%5Cfrac%7B1%7D%7B2%5E%7B2%7D%7D-%5Cfrac%7B1%7D%7B4%5E%7B2%7D%7D%20%29)
= ![1.0973731568508 \times 10^{7} \times (0.25-0.0625 )](https://tex.z-dn.net/?f=1.0973731568508%20%5Ctimes%2010%5E%7B7%7D%20%5Ctimes%20%280.25-0.0625%20%29)
= ![1.0973731568508 \times 10^{7} \times (0.1875 )](https://tex.z-dn.net/?f=1.0973731568508%20%5Ctimes%2010%5E%7B7%7D%20%5Ctimes%20%280.1875%20%29)
= ![0.20575 \times 10^{7}](https://tex.z-dn.net/?f=0.20575%20%5Ctimes%2010%5E%7B7%7D)
![\lambda= \frac{1}{0.20575 \times 10^{7}}](https://tex.z-dn.net/?f=%5Clambda%3D%20%5Cfrac%7B1%7D%7B0.20575%20%5Ctimes%2010%5E%7B7%7D%7D)
= ![4.8602 \times 10^{-7} m](https://tex.z-dn.net/?f=4.8602%20%5Ctimes%2010%5E%7B-7%7D%20m%20)
= ![486.02 \times 10^{-9} m](https://tex.z-dn.net/?f=486.02%20%5Ctimes%2010%5E%7B-9%7D%20m%20)
= ![486.02 nm](https://tex.z-dn.net/?f=486.02%20nm%20)
Now, for
= 2 and
= 3
![\frac{1}{\lambda} = 1.0973731568508 \times 10^{7} \times (\frac{1}{2^{2}}-\frac{1}{3^{2}} )](https://tex.z-dn.net/?f=%5Cfrac%7B1%7D%7B%5Clambda%7D%20%3D%201.0973731568508%20%5Ctimes%2010%5E%7B7%7D%20%5Ctimes%20%28%5Cfrac%7B1%7D%7B2%5E%7B2%7D%7D-%5Cfrac%7B1%7D%7B3%5E%7B2%7D%7D%20%29)
= ![1.0973731568508 \times 10^{7} \times (0.25-0.12 )](https://tex.z-dn.net/?f=1.0973731568508%20%5Ctimes%2010%5E%7B7%7D%20%5Ctimes%20%280.25-0.12%20%29)
= ![1.0973731568508 \times 10^{7} \times (0.13 )](https://tex.z-dn.net/?f=1.0973731568508%20%5Ctimes%2010%5E%7B7%7D%20%5Ctimes%20%280.13%20%29)
= ![0.1426585\times 10^{7}](https://tex.z-dn.net/?f=0.1426585%5Ctimes%2010%5E%7B7%7D)
![\lambda= \frac{1}{0.1426585\times 10^{7}}](https://tex.z-dn.net/?f=%5Clambda%3D%20%5Cfrac%7B1%7D%7B0.1426585%5Ctimes%2010%5E%7B7%7D%7D)
= ![7.0097 \times 10^{-7} m](https://tex.z-dn.net/?f=7.0097%20%5Ctimes%2010%5E%7B-7%7D%20m%20)
= ![700.97 \times 10^{-9} m](https://tex.z-dn.net/?f=700.97%20%5Ctimes%2010%5E%7B-9%7D%20m%20)
= ![700.97 nm](https://tex.z-dn.net/?f=700.97%20nm%20)
mass = 12.2 kg
Explanation:
To find the mass we use the following formula (Newton's Second Law of Motion):
force = mass × acceleration
mass = force / acceleration
mass = 2.32 N / 0.19 m/s²
mass = 12.2 kg
Learn more about:
Newton's Second Law of Motion
brainly.com/question/834262
#learnwithBrainly
Using the exponential decay model; we calculate "k"
We know that "A" is half of A0
A = A0 e^(k× 5050)
A/A0 = e^(5050k)
0.5 = e^(5055k)
In (0.5) = 5055k
-0.69315 = 5055k
k = -0.0001371
To calculate how long it will take to decay to 86% of the original mass
0.86 = e^(-0.0001371t)
In (0.86) = -0.0001371t
-0.150823 = -0.0001371 t
t = 1100 hours
Answer:
1. No 1 looks like a statement and not a question.
2.Ionic compounds are usually formed from the transfer of electrons from metals to Non metals. All others are Ionic compounds except HCl(Its a covalent compound).
3. The Formula would be K2S. Exchange of Radicals takes place. Sulphur has a -2 charge and potassium has a +1 charge. when they both exchange radicals... The compound is K2S.
4.Group 1 elements have only 1 electron in their outermost shell.
5. its charge will be +1 because it loses the 1 electron in its outermost shell.
6.Group 2 elements have 2electrons in their Valence shell.
7.Already answered. same as No 5.
8. Group 16;Also known as group 6. They have only 6 electrons in their outermost shell.
9.When they want to become stable... they acquire 2electrons to complete their octet... so they possess a -2 charge by forming an ion.
10. i)They form ions when Dissolve in solutions
ii) They are hard and brittle
iii) They have high boiling points