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OLga [1]
1 year ago
13

inverse process: suppose instead of dropping the mass, we had started with the mass moving up (from an initial push on the glide

r), and recorded until it stopped. how would this change how each of those systemic errors manifest (if at all)?
Physics
1 answer:
Luda [366]1 year ago
4 0

In the case of dropping we have exact data about height of dropping. But, in other case of moving up we can not exactly say the height. Here an error of measurement come.

<h3>What does acceleration due to gravity mean?</h3>

Gravitational acceleration is the acceleration that an object experiences as a result of the gravitational field. It has the SI unit m/s². Given that it has both a magnitude and a direction, it is a vector quantity. g is a unit used to measure gravitational acceleration. 9.8 m/s²is the standard value of g at sea level on the surface of the earth.

  • The acceleration caused by gravity is lower for an object positioned at a height h than for one placed on the ground.
  • The value of the gravity's acceleration (g) decreases as depth rises.
  • G has a higher value near the poles and a lower value at the equator.

To know more about acceleration due to gravity and height, visit

brainly.com/question/17276584

#SPJ4

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How would radiation occur in space?
Marizza181 [45]

Answer:

Space radiation is made up of three kinds of radiation: particles trapped in the Earth's magnetic field; particles shot into space during solar flares (solar particle events); and galactic cosmic rays, which are high-energy protons and heavy ions from outside our solar system.

Explanation:

3 0
3 years ago
You hear an _____ when sound bounces off a hard surface.
Aleksandr [31]
I think b but I’m not completely sure
7 0
4 years ago
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A sound wave of the form s = sm cos(kx - ?t + f) travels at 343 m/s through air in a long horizontal tube. At one instant, air m
Naddik [55]

Answer:

960.24 Hz

Explanation:

Here is the complete question

A sound wave of the form

S=Smcos(kx−ωt+Φ)

travels at 343 m/s through air in a long horizontal tube. At one instant, air molecule A at x = 2.000 m is at its maximum positive displacement of 6.00 nm and air molecule B at x = 2.070 m is at a positive displacement of 2.00 nm. All the molecules between A and B are at intermediate displacements. What is the frequency of the wave?

Solution

Given x₁ = 2.0 m, x₂ = 2.070 m, maximum positive displacement s = 6.00 nm at x₁, positive displacement s = 2.00 nm at x₂, velocity of wave v = 343 m/s, maximum positive displacement s₀ = 6.00 nm

Let t₀ = 0 at x₁ = 2.0 m for maximum displacement.

So, s = s₀cos(kx−ωt+Φ)

     6 = 6cos(2k - 0 + Φ) = 6cos(2k + Φ)⇒ cos(2k + Φ) = 6/6 = 1

cos(2k + Φ) = 1 ⇒ (2k + Φ) = cos⁻¹ (1) = 0 ⇒ 2k + Φ = 0

Let t₀ = 0 at x₂ = 2.070 m for displacement s = 2.00 nm.

So, s = s₀cos(kx−ωt+Φ)

     2 = 6cos(2.070k - 0 + Φ) = 6cos(2.070k + Φ)⇒ cos(2.070k + Φ) = 2/6 = 1/3

cos(2.070k + Φ) = 1/3 ⇒ (2.070k + Φ) = cos⁻¹ (1/3) = 70.53 ⇒ 2.070k + Φ = 70.53.

We now have two simultaneous equations.

2k + Φ = 0   (1)

2.070k + Φ = 70.53.    (2)

Subtracting (2) -(1)

2.070k - 2k = 70.53

0.070k = 70.53

k = 70.53/0.070 = 1007.554π/180 rad/m = 17.59 rad/m

k = 2π/λ ⇒ λ = 2π/k

and frequency, f = v/λ = v/2π/k = kv/2π = 17.59 × 343/2π = 960.24 Hz

4 0
4 years ago
The earth has a vertical electric field at the surface, pointing down, that averages 100 N/C. This field is maintained by variou
zlopas [31]

Answer:

q = 3.6 10⁵  C

Explanation:

To solve this exercise, let's use one of the consequences of Gauss's law, that all the charge on a body can be considered at its center, therefore we calculate the electric field on the surface of a sphere with the radius of the Earth

          r = 6 , 37 106 m

          E = k q / r²

          q = E r² / k

          q = \frac{100 \ (6.37 \ 10^6)^2}{9 \ 10^9}

          q = 4.5 10⁵ C

Now let's calculate the charge on the planet with E = 222 N / c and radius

           r = 0.6 r_ Earth

           r = 0.6 6.37 10⁶ = 3.822 10⁶ m

           E = k q / r²

            q = E r² / k

            q = \frac{222 (3.822 \ 10^6)^2}{ 9 \ 10^9}

            q = 3.6 10⁵  C

4 0
3 years ago
Which of the following parts of a nuclear power plant is turned by steam? Select one: a. control rods b. reactor vessel c. turbi
SOVA2 [1]

A nuclear power plant is defined as a thermal power station where electricity is generated by the help of sustainable nuclear fission.

A nuclear power plant needs nuclear reactor as the thermal energy generator .The reactor has various parts where fissionable radioactive material will undergo nuclear fission .Through this process high amount of thermal energy is released which is allowed to water to generate steam.

The steam produced in the reactor drives the turbine which is connected to the generator.Due to the electromagnetic induction the generator will produce electricity.

The control rods present in the nuclear reactor will control the rate of fission by absorbing the thermal neutrons.

Hence the correct answer of the question is C i.e Turbine.

8 0
3 years ago
Read 2 more answers
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