1answer.
Ask question
Login Signup
Ask question
All categories
  • English
  • Mathematics
  • Social Studies
  • Business
  • History
  • Health
  • Geography
  • Biology
  • Physics
  • Chemistry
  • Computers and Technology
  • Arts
  • World Languages
  • Spanish
  • French
  • German
  • Advanced Placement (AP)
  • SAT
  • Medicine
  • Law
  • Engineering
Marta_Voda [28]
1 year ago
15

using the terms liquid, vapor, and liquid-vapor mixture, describe the condition of the refrigerant at the following points of th

e cycle: 1. entering evaporator 2. leaving evaporator 3. entering compressor 4. leaving compressor 5. entering condenser 6. leaving condenser, entering receiver
Physics
1 answer:
blsea [12.9K]1 year ago
7 0

These are the condition of the refrigerant at the following points of the refrigeration cycle:

  1. Entering evaporator: liquid-vapor mixture
  2. Leaving evaporator: vapor
  3. Entering compressor: vapor (low-pressure)
  4. Leaving compressor: vapor (high-pressure)
  5. Entering condenser: liquid-vapor mixture (starts as vapor)
  6. Leaving condenser: liquid

A vapor compression refrigeration system is a system consisting of circulating refrigerant through stages of a closed system to create a cold environment that's conducive to preserving and storing products.

There are several parts in a refrigeration system that can change the condition of refrigerant during certain points of the cycle.

  • Evaporator is a part that turns the liquid form of refrigerant into its gaseous-form (vapor).
  • Compressor is a part that compresses the refrigerant to a higher-pressure.
  • Condenser is a part that condense the gaseous-form of refrigerant into a liquid state through cooling process.

Learn more about CFC at brainly.com/question/28245894

#SPJ4

You might be interested in
Three individual point charges are placed at the following positions in the x-y plane:Q3= 5.0 nC at (x, y) = (0,0);Q2= -3.0 nC a
ozzi

Answer:

Explanation:

net force exerted on charge Q₃, exerted by charges Q₁and Q₂, will be  zero

if net  electric field due to charges Q₁ and Q₂  at origin is zero .

electric field due to Q₂

= 9 X 10⁹ X 3 x10⁹ / .04²

electric field due to Q₁

= 9 X 10⁹ X Q₁ / .02²

For equilibrium

9 X 10⁹ X Q₁ / .02² = 9 X 10⁹ X 3 x10⁻⁹ / .04²

Q₁  = 3 X10⁻⁹ x .02² / .04²

= 3 / 4 x 10⁻⁹

.75 x 10⁻⁹  C

8 0
3 years ago
Which of the following best explains why clear-cutting forests is more destructive than selectively cutting down trees in forest
garri49 [273]
<span>The answer is a. cutting trees reduce fertility and eliminates animal habitats. Plant material is essential in maintaing soil fertility. Leaves and branches decay to form humus; removing trees decreases the organic content. Trees are home to many animal species, including birds, insects and amphibians. Some trees are even support or home to other plants. Examples include epiphytes in the rainforest ecosystem. Clear cutting forests disrupts whole communities and ecosystems. </span>
6 0
4 years ago
Read 2 more answers
What is the purpose of the three R’s of resource management?
Natalka [10]
The answer is A sorry i would of expalined why but i have to go :c
8 0
4 years ago
Read 2 more answers
A car travels at uniform acceleration over a tine interval of 20.0s. its initial velocity is 11.0m/s and its final velocity is 3
SIZIF [17.4K]

Since the acceleration is uniform, we can calculate it from the data we are given:

a = (vf - vi)/2

where vf=33 m/s and vi=11 m/s

Then use Suvat's equation:

x(t) = vi*t + 0.5 * a * t

where t=20s

3 0
4 years ago
A 45.0 - kg girl is standing on a 150. - kg plank. The plank, originally at rest, is free to slide on a frozen lake, which is a
Mrac [35]

Answer:

The velocity relative to the surface of the ice is 6.5 m/s.

Explanation:

Given that,

Mass of girl m= 45.0 kg

Mass of plank M= 150 kg

Velocity = 1.50 m/s

We need to calculate the velocity relative to the surface of the ice

Using conservation of momentum

mv_{1}+Mv_{2}=(m+M)v

Here, v_{2}=0 because plank at rest

v_{1}=\dfrac{m+M}{m}\times v

Put the value into the formula

v_{1}=\dfrac{45+150}{45}\times1.50

v_{1}=6.5\ m/s

Hence, The velocity relative to the surface of the ice is 6.5 m/s.

6 0
3 years ago
Other questions:
  • A scaffold of mass 60 kg and length 5.0 m is supported in a horizontal position by a vertical cable at each end. Its center of g
    14·1 answer
  • The headlights are shining on a truck travelling at 100 km/h. The speed of the light from the headlights relative to the road wi
    10·2 answers
  • Converging trade winds produce a calm region called
    8·2 answers
  • A parallel-plate vacuum capacitor is connected to a battery and charged until the stored electric energy is . The battery is rem
    12·1 answer
  • A truck covers 32.0 m in 8.70 s while smoothly slowing down to final speed of 2.10 m/s. (a) Find its original speed. Incorrect:
    5·1 answer
  • A heat engine operates at 30% of its maximum possible efficiency and needs to do 995 J of work. Its cold reservoir is at 22 ºC a
    5·1 answer
  • A force is an effort needed to change the
    13·1 answer
  • What type of energy does friction produce?
    8·1 answer
  • A 12 kg<br> mass is lifted to a height of 2 m. What is its potential energy<br> at this position?
    5·2 answers
  • What is the purpose of chloroplasts, and why do you think it is missing from the root hair cell?
    9·1 answer
Add answer
Login
Not registered? Fast signup
Signup
Login Signup
Ask question!