Answer:
moves into a region of higher potential
Potential difference = 835 V
Ki = 835 eV
Explanation:
given data
initial speed = 400000 m/s
solution
when proton moves against a electric field so that it will move into higher potential region
and
we know Work done by electricfield W is express as
W = KE of proton K
so
q × V = 0.5 × m × v² ......................1
put here va
lue
1.6 × × V = 0.5 × 1.67 × × 400000²
Potential difference V = 1.336 × 10-16 / 1.6 × 10-19
Potential difference = 835 V
and
KE of proton in eV is express as
Ki = V numerical
Ki = 835 eV
Answer:
girl what- I can't answer this but I need points so I'ma just put this random lol sorry tho . ask the tutor
Answer: 2.17 s
Explanation:
The described situation is related to projectile motion (also known as parabolic motion). So, this kind of motion has a vertical component and a horizontal component; however, in this case we will only need the equation related to the horizontal displacement :
Where:
is the arrow's horizontal displacement
is the arrow's initial velocity
is the angle
is the time the arrow is in the air
Isolating :
Solving with the given data:
This is the time the arrow is in the air
Answer: The electric repulsion between the two protons is stronger than the gravitational attraction.
Explanation: Please see the attachments below