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ivann1987 [24]
3 years ago
15

A 45.0 - kg girl is standing on a 150. - kg plank. The plank, originally at rest, is free to slide on a frozen lake, which is a

flat, frictionless surface. The girl begins to walk along the plank at a constant velocity of 1.50 m/s to the right relative to the plank. What is her velocity relative to the surface of the ice?
Physics
1 answer:
Mrac [35]3 years ago
6 0

Answer:

The velocity relative to the surface of the ice is 6.5 m/s.

Explanation:

Given that,

Mass of girl m= 45.0 kg

Mass of plank M= 150 kg

Velocity = 1.50 m/s

We need to calculate the velocity relative to the surface of the ice

Using conservation of momentum

mv_{1}+Mv_{2}=(m+M)v

Here, v_{2}=0 because plank at rest

v_{1}=\dfrac{m+M}{m}\times v

Put the value into the formula

v_{1}=\dfrac{45+150}{45}\times1.50

v_{1}=6.5\ m/s

Hence, The velocity relative to the surface of the ice is 6.5 m/s.

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4 years ago
In atoms, electrons surround the nucleus in
nasty-shy [4]

In atoms, electrons surround the nucleus in specific energy levels.

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<u>Explanation: </u>

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8 0
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Once you start pulling your object with less force than friction, what should you expect your object to do? What about when your
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#Case -1

If Pulling force is less than frictional force the object won't move .

#Case-2

If Pulling force is greater than frictional force then object will be .

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\\ \sf\longmapsto F_L=\mu sN

u s is coefficient of static friction and N is normal reaction

Or

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