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10 months ago

How much energy is required to heat 40.7 g of water (h2o) from −10∘c to 70∘c?

Physics

1 answer:

marin [14]10 months ago

8 0

The amount of energy that is required was found to be 4.184 J

define energy ?

In physics, energy (from Ancient Greek: v, enérgeia, "activity") is a quantitative quality that is transmitted to a body or a physical system and is observable in the execution of work as well as in the form of heat and light. The law of conservation of energy holds that energy can be transformed in form but cannot be generated or destroyed. The joule is the International System of Units (SI) unit of measurement for energy (J).

The kinetic energy of a moving object, the potential energy stored by an object (for example, due to its position in a field), the elastic energy stored in a solid object, chemical energy associated with chemical reactions, radiant energy carried by electromagnetic radiation, and internal energy contained within a thermodynamic system are all examples of common forms of energy. All living creatures continually absorb and expel energy.

So, to do that, we'll set up our equation so that q equals 40.7, and then the specific heat of water is 4.184 joules per gramme, times degrees celsius, and since I'm keeping this in grammes, this is the correct value of c, and then our final temperature minus our initial temperature, so 70 degrees celsius minus negative 10 degrees celsius, and that gives us 40.7 times 4.184 times 80, which gives us the value of q

To learn more about energy follow the given link:brainly.com/question/2003548

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HELPPP IM DESPERATE

damaskus [11]

the first one cuz I know

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2 years ago

A box accidentally drops from a truck traveling at a speed of 20.0 m/s and slides along the ground for a distance of 30.0 m Calc

Hoochie [10]

Answer:

a= - 6.667 m/s²

Explanation:

Given that

The initial speed of the box ,u= 20 m/s

The final speed of the box ,v= 0 m/s

The distance cover by box ,s= 30 m

Lets take the acceleration of the box = a

We know that

v²= u ² + 2 a s

Now by putting the values in the above equation we get

0²=20² + 2 a x 30

$a=- \dfrac{20^2}{2\times 30} \ m/s^2$

a= - 6.667 m/s²

Negative sign indicates that velocity and acceleration are in opposite direction.

Therefore the acceleration of the box will be - 6.667 m/s² .

6 0

2 years ago

PLS HELP ASAP WILL MARK BRAIN and pls explain your answer....

lora16 [44]

Answer:

it is sublimation because There are three ways heat is transferred into and through the atmosphere:

radiation.

conduction.

convection.

Explanation:

please mark me as brainliest as you wrote over there

5 0

2 years ago

A single-phase electrical load draws 600KVA at 0.6 power factor lagging. a) Find the real and reactive power absorbed by the loa

Whitepunk [10]

Answer:

(a). The reactive power is 799.99 KVAR.

(c). The reactive power of a capacitor to be connected across the load to raise the power factor to 0.95 is 790.05 KVAR.

Explanation:

Given that,

Power factor = 0.6

Power = 600 kVA

(a). We need to calculate the reactive power

Using formula of reactive power

$Q=P\tan\phi$ ...(I)

We need to calculate the $\phi$

Using formula of $\phi$

$\phi=\cos^{-1}(Power\ factor)$

Put the value into the formula

$\phi=\cos^{-1}(0.6)$

$\phi=53.13^{\circ}$

Put the value of Φ in equation (I)

$Q=600\tan(53.13)$

$Q=799.99\ kVAR$

(b). We draw the power triangle

(c). We need to calculate the reactive power of a capacitor to be connected across the load to raise the power factor to 0.95

Using formula of reactive power

$Q'=600\tan(0.95)$

$Q'=9.94\ KVAR$

We need to calculate the difference between Q and Q'

$Q''=Q-Q'$

Put the value into the formula

$Q''=799.99-9.94$

$Q''=790.05\ KVAR$

Hence, (a). The reactive power is 799.99 KVAR.

(c). The reactive power of a capacitor to be connected across the load to raise the power factor to 0.95 is 790.05 KVAR.

8 0

3 years ago

At the equator, the radius of the Earth is approximately 6370 km. A plane flies at a very low altitude at a constant speed of v

Anna007 [38]

To solve this problem we will apply the concepts related to the kinematic equations of linear motion. For this purpose we will define the speed as the distance traveled in a given period of time. Here the distance is equivalent to the orbit traveled around the earth, that is, a circle. Approaching the height of the aircraft with the radius of the earth, we will have the following data,

$R= 6370*10^3 m$