Question

A car moving eastward along a straight road increases its speed uniformly from 16 m/s to 32 m/s in 10.0 s.

Answer 1

Answer:

a)$a= 1.6 m/s^2$

b)V= 24 m/s

c)d=240 m

Explanation:

Given that

u = 16 m/s

v= 32 m/s

t= 10 s

The average acceleration = a

We know v = u +at

32 = 16 + a x 10

$a=\dfrac{32-16}{10}\ m/s^2$

$a= 1.6 m/s^2$

$d=ut+\dfrac{1}{2}at^2$

d=displacement

$d=16\times 10+\dfrac{1}{2}\times 1.6\times 10^2$

d=240 m

The average velocity

$V=\dfrac{d}{t}$

$V=\dfrac{240}{10}\ m/s$

V= 24 m/s

a)$a= 1.6 m/s^2$

b)V= 24 m/s

c)d=240 m