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Iteru [2.4K]
1 year ago
3

Two objects with the same mass have the same force applied to them. What can be said of their acceleration?

Physics
2 answers:
Nostrana [21]1 year ago
6 0

The force acting on two bodies will be the same if they have same mass and same acceleration. But the acceleration is dependant on the net force of the body and thus option C is correct. The net force of the body is 10 N to the right.

<h3>What is force?</h3>

Force is an external agent or factor which change an object from its state of rest or motion. The force to be applied depends on the mass and acceleration of the body by the equation F = ma.

Acceleration of a moving body is dependant on the direction and thus the direction of force and net force. Thus the two objects having the same mass and same force f applied to them, the acceleration may not be the same. Thus option C is correct.

The two force acting on a body in opposite direction will cancel each other in magnitude. Thus 20N of force to the right will be cancel by 20 N to the left. Remaining 10N will be there to the right direction. Hence, option D is correct.

To find more about force, refer the link below:

brainly.com/question/13191643

#SPJ2

professor190 [17]1 year ago
6 0

Answer:

Explanation:

A. <u>Their acceleration will be the same.</u>    F=ma, a = F/m.  If F and m are the same, acceleration will be the same.

B. Their acceleration will be different.

C. Their acceleration will depend on their net force, which is not provided.

D. Their acceleration will depend on their weight, which is not provided.

======

A force of 30 N to the right is applied to an object. An opposite force of 20 N to the left is applied to the same object. What is the net force applied to the object?

A. 10 N to the left

B. 50 N to the right

C. 50 N to the left

D. <u><em>10 N to the right</em></u>

Add the two vectors:  30R = +30, 20L = -20 Sum = +10 or 10R

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Density d=m/V

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Convert 1 second into solar day.
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3 years ago
The index of refraction for red light in water is 1.331 and that for blue light is 1.340. If a ray of white light enters the wat
kobusy [5.1K]

Answer:

Angle of refraction for red light is 43.01^{\circ}

Angle of refraction for blue light is  42.68^{\circ}    

Explanation:

It is given refractive index for red light is \mu _{red}=1.331

Refractive index of blue light \mu _{blue}=1.340

Angle of incidence i=65.30^{\circ}

According to law of refraction \mu =\frac{sini}{sinr}

For red light 1.331 =\frac{sin65.30^{\circ}}{sinr}

1.331 =\frac{0.908}{sinr}

sinr=0.682

r=43.01^{\circ}

Therefore angle of refraction for red light is 43.01^{\circ}

Similarly for blue light 1.340 =\frac{sin65.30^{\circ}}{sinr}

1.340 =\frac{0.908}{sinr}

sinr=0.677

r = 42.68^{\circ}

Therefore angle of refraction for blue light is  42.68^{\circ}

6 0
3 years ago
A container of gas is at a pressure of 3.7 x 10^5 Pa. How much work is done by the gas if its volume expands by 1.6 m^3 ?
Dmitriy789 [7]

Answer:

592000 J

Explanation:

We'll begin by converting 3.7×10⁵ Pa to Kg/ms². This can be obtained as follow:

1 Pa = 1 Kg/ms²

Therefore,

3.7×10⁵ Pa = 3.7×10⁵ Kg/ms²

Next, we shall determine the workdone.

Workdone is given by the following equation:

Workdone (Wd) = pressure (P) × change in volume (ΔV)

Wd = PΔV

With the above formula, the work done can be obtained as follow:

Pressure (P) = 3.7×10⁵ Kg/ms²

Change in volume (ΔV) = 1.6 m³

Workdone (Wd) =?

Wd = PΔV

Wd = 3.7×10⁵ × 1.6

Wd = 592000 Kgm²/s²

Finally, we shall convert 592000 Kgm²/s² to Joule (J). This can be obtained as follow:

1 Kgm²/s² = 1 J

Therefore,

592000 Kgm²/s² = 592000 J

Therefore, the Workdone is 592000 J.

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3 years ago
A cat (5kg) has a potential energy of 8J. The cat is stuck on top of a bookshelf and then falls off the bookshelf. What is the v
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Answer:

176J

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